简而言之,我知道这个问题没有意义,让我清楚一点,如果我点击它会改变为X,反之亦然如何解决这个问题? 就像我不知道如何禁用它们以保持放置一样,你们也知道如何用for循环重置游戏而不是手动操作
HTML:
<!DOCTYPE html>
<html>
<head>
<title>Tic Tac Toe</title>
<script text="javascript" src="tic.js"></script>
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<center>
<body>
<h1 style="font-family:arial;">Tic-Tac-Toe</h1>
<table>
<tr>
<td id = "case1" onclick="display_input('case1')"></td>
<td id = "case2" onclick="display_input('case2')"></td>
<td id = "case3" onclick="display_input('case3')"></td>
</tr>
<tr>
<td id = "case4" onclick="display_input('case4')"></td>
<td id = "case5" onclick="display_input('case5')"></td>
<td id = "case6" onclick="display_input('case6')"></td>
</tr>
<tr>
<td id = "case7" onclick="display_input('case7')"></td>
<td id = "case8" onclick="display_input('case8')"></td>
<td id = "case9" onclick="display_input('case9')"></td>
</tr>
</table>
<footer>
<p>Copyright© 2014</p>
</footer>
</body>
</center>
</html>
使用Javascript:
var player_one = 1;
function display_input(square){
if ( player_one == 1 ){
document.getElementById(square).innerHTML = "X";
player_one = 0;
} else {
document.getElementById(square).innerHTML = "O";
player_one = 1;
}
}
function reset() {
document.getElementById("case1").innerHTML = "";
document.getElementById("case2").innerHTML = "";
document.getElementById("case3").innerHTML = "";
document.getElementById("case4").innerHTML = "";
document.getElementById("case5").innerHTML = "";
document.getElementById("case6").innerHTML = "";
document.getElementById("case7").innerHTML = "";
document.getElementById("case8").innerHTML = "";
document.getElementById("case9").innerHTML = "";
}
答案 0 :(得分:1)
您可以随时检查方形元素是否为空,如果不是,则不要执行任何操作:
function display_input(square) {
//We get the associated DOM element
var element = document.getElementById(square);
//If the element already contains something, then don't change it
if(element.innerHTML != "") return;
if(player_one == 1) {
element.innerHTML = "X";
player_one = 0;
} else {
element.innerHTML = "O";
player_one = 1;
}
}
答案 1 :(得分:0)
通过将以下内容添加到display_input(square)来覆盖方块的onclick函数
document.getElementById(square).onclick = function() {return};