Question

我实际上是将我的代码从mysql转换为mysqli。我有一个用mysql编写的代码，它将查询结果作为对象返回。我正在使用ExtJS4和MVCS架构来处理php文件返回的结果。这是原始的mysql php代码：

<?php
require_once('../../db_mysqli.php');
require_once '../../lib/response.php';
require_once '../../lib/request.php';

class user{ 
    var $user_id;
    var $first_name;
    var $last_name;
    var $sex;
    var $birth_date;
    var $email;
    var $password;
}

$total;

if(isset($_GET['email'])){
    $email = $_GET['email'];
    $password = $_GET['password'];

    $query = "SELECT * FROM user_details 
                    WHERE email = '$email' AND password = '$password'";

    $result = mysql_query($query);
    $totalquery = mysql_query("SELECT COUNT(*) FROM user_details 
            WHERE email = '$email'
            AND password = '$password'");

    $total = mysql_fetch_array($totalquery);
}

$total =($total[0]);
$query_array=array();
$i=0;

//Iterate all Select
while($row = mysql_fetch_array($result)){
    //Create New User instance
    $inputData = new user();
    //Fetch User Info

    $inputData->user_id=$row['user_id'];        
    $inputData->first_name=$row['first_name'];
    $inputData->last_name=$row['last_name'];
    $inputData->sex=$row['sex'];
    $inputData->birth_date=$row['birth_date'];
    $inputData->email=$row['email'];
    $inputData->password=$row['password'];

    //Add User to ARRAY
    $query_array[$i]=$inputData;
    $i++;
}
mysql_close($con);

//Creating Json Array needed for Extjs Proxy
$res = new Response();
$res->success = true;
$res->message = "Loaded read data";
$res->total = $total;
$res->data = $query_array;
//Printing json ARRAY
print_r($res->to_json());
?>

我所做的是创建一个对象来存储结果查询的行，我查询数据库，然后迭代结果集。在每次迭代期间，我创建一个holder对象并将值存储在那里，然后将其保存到另一个与响应对象一起传回的数组中。该代码效果很好。

但是，我现在正在使用mysqli，到目前为止，这是我尝试过的。请注意，我使用了相同的类，我只会显示查询的部分并将结果保存到对象。

//I used some hard coded values first
$query = "SELECT * FROM user_details 
    WHERE email = 'test@yahoo.com' AND password = '123'";
$result = $mysqli->query($query);

我试过这个：

$query_array=array();
$i=0;

//Iterate all Select
while($row = $result->fetch_array(MYSQLI_ASSOC)){
    //Create New User instance
    $inputData = new user();
    //Fetch User Info

    $inputData->user_id=$row['user_id'];        
    $inputData->first_name=$row['first_name'];
    $inputData->last_name=$row['last_name'];
    $inputData->sex=$row['sex'];
    $inputData->birth_date=$row['birth_date'];
    $inputData->email=$row['email'];
    $inputData->password=$row['password'];

    //Add User to ARRAY
    $query_array[$i]=$inputData;
    $i++;
}

$result->close();
$mysqli->close();

$res = new Response();
$res->success = true;
$res->total = $total;
$res->data = $query_array;
print_r($res->to_json());

我还试图保存结果集：

if ($result = $mysqli->query($query)) {

    /* fetch object array */
    while ($obj = $result->fetch_object()) {
        $query_array[$i]=$obj;
        $i++
    }
}

但是，当我使用localhost:8888/../../../../../../readUser.php从浏览器中调用它们时，我看不到print_r函数调用的任何输出，这意味着我在某处有错误。

任何人都可以帮助解决我的小问题吗？很感谢任何形式的帮助。谢谢。

Answer 1

道歉。我有一个迷路$res->message.= $result;线，搞砸了很多东西。这是使它工作的代码。

//check for some variables that may or may not be passed 
if(isset($_GET['email'])){
    $email = $_GET['email'];
    $password = $_GET['password'];

    $query = "SELECT * FROM user_details 
                    WHERE email = '$email' AND password = '$password'";     
    //execute query here
    $result = $mysqli->query($query);
    $total = 1;

}

//I used the associative style since I don't want to guess column index 
while($row = $result->fetch_array(MYSQLI_ASSOC)){
    //Create New User instance
    $inputData = new user();
    //Fetch User Info

    $inputData->user_id=$row['user_id'];        
    $inputData->first_name=$row['first_name'];
    $inputData->last_name=$row['last_name'];
    $inputData->sex=$row['sex'];
    $inputData->birth_date=$row['birth_date'];
    $inputData->email=$row['email'];
    $inputData->password=$row['password'];

    //Add User to ARRAY
    $query_array[$i]=$inputData;
    $i++;
}

//close result set and sqli connection
$result->close();
$mysqli->close();

//create your response object
$res = new Response();
$res->message = "Message Start. ";

$res->success = true;
$res->total = $total;
$res->data = $query_array; //set the data to your query_array result
print_r($res->to_json()); //send back to extJS

PHP5 - 将mysqli行结果保存为对象？

1 个答案: