结构不正常？

Question

Fraction AddFractions(const Fraction& frac1, const Fraction& frac2)
{
    Fraction frac3;

    if (frac1.denom == frac2.denom)
    {
        frac3.num = frac1.num + frac2.num;
        frac3.denom = frac1.denom;          
    }
    else
    {
        frac3.denom = (frac1.denom * frac2.denom);
        frac3.num = (frac1.num * frac2.denom) + (frac2.num * frac1.denom);          
    }
    return frac3;
}

这是我的原型，有一个结构定义为Fraction int num和int denom当我调用它只是给我回垃圾的功能时？我不知道它有什么问题。请帮忙。 =（

    cout << "Please enter two Fractions" << endl;
    cout << endl;
    GetFraction(frac1); 
    cout << "Your fisrt fraction is: ";
    PrintFraction(frac1);
    cout << endl;
    cout << endl;
    GetFraction(frac2);
    cout << "Your second fraction is: ";
    PrintFraction(frac2);
    cout << endl;


    do
    {
        choice1 = MathMenu();
        if (choice1 == ErrorOpt)
        {
            cout << "There was an error with what you have entered" << endl;
        }
        else if(choice1 != QuitOpt)
        {

            // do the math options 
            switch (choice1)
            {
            case AddOpt:
                AddFractions(frac1, frac2);
                break;
            case SubtractOpt:
                SubtractFractions(frac1, frac2);
                break;
            case MultiplyOpt:
                MultiplyFractions(frac1, frac2);
                break;
            case DivideOpt:
                DivideFractions(frac1, frac2);
                break;
            }
            //print the results 
            PrintFraction(frac1);
            PrintMathOption(choice1);
            PrintFraction(frac2);
            cout << " = ";
            Standardize(frac3);
            Reduce(frac3);
            PrintFraction(frac3);
            cout << endl;
            Pause();

Answer 1

您应该指定frac3例如：

frac3 = AddFractions(frac1, frac2);

Answer 2

从我的代码中可以看出来;在以下范围内没有变量frac3：

        Standardize(frac3);
        Reduce(frac3);
        PrintFraction(frac3);

你的数学函数正在被调用，但你没有获得回报。