为什么这个程序在运行
时给我一个“Debug Assertion Failed”错误信息#include "stdafx.h"
#include "iostream"
#include "fstream"
#include "string"
using namespace std;
int conv_ch(char b)
{
int f;
f=b;
b=b+0;
switch(b)
{
case 48:
f=0;
break;
case 49:
f=1;
break;
case 50:
f=2;
break;
case 51:
f=3;
break;
case 52:
f=4;
break;
case 53:
f=5;
break;
case 54:
f=6;
break;
case 55:
f=7;
break;
case 56:
f=8;
break;
case 57:
f=9;
break;
default:
f=0;
}
return f;
}
class Student
{
public:
string id;
size_t id_len;
string first_name;
size_t first_len;
string last_name;
size_t last_len;
string phone;
size_t phone_len;
string grade;
size_t grade_len;
void print();
void clean();
};
void Student::clean()
{
id.erase (id.begin()+6, id.end());
first_name.erase (first_name.begin()+15, first_name.end());
last_name.erase (last_name.begin()+15, last_name.end());
phone.erase (phone.begin()+10, phone.end());
grade.erase (grade.begin()+2, grade.end());
}
void Student::print()
{
int i;
for(i=0;i<6;i++)
{
cout<<id[i];
}
cout<<endl;
for(i=0;i<15;i++)
{
cout<<first_name[i];
}
cout<<endl;
for(i=0;i<15;i++)
{
cout<<last_name[i];
}
cout<<endl;
for(i=0;i<10;i++)
{
cout<<phone[i];
}
cout<<endl;
for(i=0;i<2;i++)
{
cout<<grade[i];
}
cout<<endl;
}
int main()
{
Student k[80];
char data[1200];
int length,i,recn=0;
int rec_length;
int counter = 0;
fstream myfile;
char x1,x2;
char y1,y2;
char zz;
int ad=0;
int ser,j;
myfile.open ("example.txt",ios::in);
int right;
int left;
int middle;
string key;
while(!myfile.eof()){
myfile.get(data,1200);
char * pch;
pch = strtok (data, "#");
printf ("%s\n", pch);
j=0;
for(i=0;i<6;i++)
{
k[recn].id[i]=data[j];
j++;
}
for(i=0;i<15;i++)
{
k[recn].first_name[i]=data[j];
j++;
}
for(i=0;i<15;i++)
{
k[recn].last_name[i]=data[j];
j++;
}
for(i=0;i<10;i++)
{
k[recn].phone[i]=data[j];
j++;
}
for(i=0;i<2;i++)
{
k[recn].grade[i]=data[j];
j++;
}
recn++;
j=0;
}
//cout<<recn;
string temp1;
size_t temp2;
int temp3;
for(i=0;i<recn-1;i++)
{
for(j=0;j<recn-1;j++)
{
if(k[i].id.compare(k[j].id)<0)
{
temp1 = k[i].first_name;
k[i].first_name = k[j].first_name;
k[j].first_name = temp1;
temp2 = k[i].first_len;
k[i].first_len = k[j].first_len;
k[j].first_len = temp2;
temp1 = k[i].last_name;
k[i].last_name = k[j].last_name;
k[j].last_name = temp1;
temp2 = k[i].last_len;
k[i].last_len = k[j].last_len;
k[j].last_len = temp2;
temp1 = k[i].grade;
k[i].grade = k[j].grade;
k[j].grade = temp1;
temp2 = k[i].grade_len;
k[i].grade_len = k[j].grade_len;
k[j].grade_len = temp2;
temp1 = k[i].id;
k[i].id = k[j].id;
k[j].id = temp1;
temp2 = k[i].id_len;
k[i].id_len = k[j].id_len;
k[j].id_len = temp2;
temp1 = k[i].phone;
k[i].phone = k[j].phone;
k[j].phone = temp1;
temp2 = k[i].phone_len;
k[i].phone_len = k[j].phone_len;
k[j].phone_len = temp2;
}
}
}
for(i=0;i<recn-1;i++)
{
k[i].clean();
}
char z;
string id_sear;
cout<<"Enter 1 to display , 2 to search , 3 to exit:";
cin>>z;
while(1){
switch(z)
{
case '1':
for(i=0;i<recn-1;i++)
{
k[i].print();
}
break;
case '2':
cin>>key;
right=0;
left=recn-2;
while(right<=left)
{
middle=((right+left)/2);
if(key.compare(k[middle].id)==0){
cout<<"Founded"<<endl;
k[middle].print();
break;
}
else if(key.compare(k[middle].id)<0)
{
left=middle-1;
}
else
{
right=middle+1;
}
}
break;
case '3':
exit(0);
break;
}
cout<<"Enter 1 to display , 2 to search , 3 to exit:";
cin>>z;
}
return 0;
}
程序从文件example.txt中读取
313121crewwe matt 0114323111A #
433444cristinaee john 0113344325A+#
324311matte richee 3040554032B #
这个想法是用文本seprator记录结构读取固定大小的字段结构
答案 0 :(得分：6)
断言失败是由您使用无效参数调用的标准C ++库函数之一引发的。在调试器中运行它，你应该看到究竟是什么电话。
有一件事看起来很可疑：在Student::clean中，您可以拨打电话：
first_name.erase (first_name.begin()+15, first_name.end());
如果first_name的长度小于15，则可能导致断言失败或其他错误。