Question

我有一个读取文件的程序，但我需要我的程序以某种方式读取文件。以下是程序读取的文件的样子：

Sample ID   Date    Time    Elem    Conc (Samp) Samp Units
381220-1    11/17/2014  7:14:57 PM  Y       %
381220-1    11/17/2014  7:14:57 PM  Ge      %
381220-1    11/17/2014  7:14:57 PM  Ge      %
381220-1    11/17/2014  7:14:57 PM  Al  0.008739442 mg/L
381220-1    11/17/2014  7:14:57 PM  As  0.006080418 mg/L
381220-1    11/17/2014  7:14:57 PM  B   0.016079117 mg/L
381220-1    11/17/2014  7:14:57 PM  Ba  -0.000985422    mg/L
381220-1    11/17/2014  7:14:57 PM  Be  -0.00025851 mg/L
381220-1    11/17/2014  7:14:57 PM  Ca  -0.012101454    mg/L
381220-1    11/17/2014  7:14:57 PM  Cd  -0.001148811    mg/L
381220-1    11/17/2014  7:14:57 PM  Ce  -0.045899969    mg/L
381220-2    11/17/2014  7:14:57 PM  Al  2.007892442 mg/L
381220-2    11/17/2014  7:14:57 PM  As  2.006080418 mg/L

我需要我的程序来获取示例381220-1的SampleID并将所有元素（Y，Ge，As等）与结果/值一起放在一行中，这样它应该是这样的。

381220-1, Al, 0.008739442, mg/L, As, 0.006080418, mg/L, etc.  
381220-2, Al, 0.008739442, mg/L, As, 2.006080418, mg/L, etc.

我尝试了不同的方法来解决这个问题，但仍然无法得到它。这就是我所做的。

try{
        BufferedReader br = new BufferedReader(new FileReader("381220.csv"));
        BufferedReader br2 = new BufferedReader(new FileReader("381220.csv"));
        FileWriter fw = new FileWriter("file.txt", false);
        PrintWriter pw = new PrintWriter(fw);    

        String line = null;
        String line2 = null;
        String[] value = null;
        String[] value2 = null;

        ArrayList<String> Queuelist = new ArrayList<String>();
        ArrayList<String> lineoftxt = new ArrayList<String>();



        while((line = br.readLine()) != null){
            if(line.contains("Sample")){
                continue;
            }

            value = line.split(","); 
            int k = 0;
            for(String S : value){             
                //System.out.println("Value ["+k+"] = " + S);
                k++;
            } 

            Queuelist.add(value[0]+",");

        }

        for(String s : Queuelist){ 
            //System.out.println(s); 
        }



        br.close();   
        pw.close();


        Queuelist = new ArrayList<String>(new LinkedHashSet<String>(Queuelist));

        Set<String> toRetain = new TreeSet<String>(String.CASE_INSENSITIVE_ORDER);
        toRetain.addAll(Queuelist);
        Set<String> set = new LinkedHashSet<String>(Queuelist);
        set.retainAll(new LinkedHashSet<String>(toRetain));
        Queuelist = new ArrayList<String>(set);

        for(String s : Queuelist){
            //System.out.println(s);
        }

        while((line2 = br2.readLine()) != null){ 
            if(line2.contains("Sample") || line2.contains("Y") || line2.contains("Ge")){
                continue;
            }

            value2 = line2.split(","); 
            int k = 0;
            for(String S : value2){               
                //System.out.println("Value ["+k+"] = " + S);
                k++;
            } 

            lineoftxt.add(line2);

            if(Queuelist.get(0).contains(lineoftxt.get(0))){
                System.out.println(Queuelist.get(0)+","+lineoftxt.get(0));
            }



        } 




        for(String s : lineoftxt){
            //System.out.println(s);
        }


        br2.close();  
        }
    catch(IOException e){}

有任何建议可以指导我完成此操作。谢谢！

Answer 1

您可以为要分组的其余数据创建一个Whatever和final String id;的班级List<WhateverDetail> detailList。使用Map<String, Whatever>对每个ID的所有Whatever进行分组，在ID已注册的情况下恢复现有的Whatever实例，并填写WhateverDetail的新实例以添加{ {1}}。

使用arraylists或其他数据结构读取和操作数据

1 个答案: