Question

我正在创建一个采用这样的JSON的API：

 "hightlights":[
  {
     "title":"Fun",
     "url":"fun/index.html",
     "queries":
     [
        "music",
        "artists",
        "events",
        "internet"
     ]
  },
  {
     "title":"Internet",
     "url":"internet/index.html",
     "queries":
     [
        "javascript",
        "web",
        "internet",
     ]
  }
 ]

我需要使用用户给出的单词过滤JSON并使用另一个JSON返回，其中只有包含＆＃34;查询＆＃34;中的单词的对象。

 If word === 'music', receive:
 {
     "title":"Fun",
     "url":"fun/index.html",
     "queries":[
        "music",
        "artists",
        "events",
        "internet"
     ]
 }

 If word === 'internet', receive:
 {
     {
     "title":"Fun",
     "url":"fun/index.html",
     "queries":[
        "music",
        "artists",
        "events",
        "internet"
     ]
  },
  {
     "title":"Internet",
     "url":"internet/index.html",
     "queries":[
        "javascript",
        "web",
        "internet",
     ]
  }

我的问题是如何嵌套这个值？如果有人能给我一些例子......我会感激......

Answer 1

尝试以下方法：

function getResult(filterBy, objList) {
  return objList.hightlights.filter(function(obj) {
   return obj.queries.some(function(item){
     return item.indexOf(filterBy) >= 0;
   });
 });
}

输入＃1：

getResult("internet", yourObject);

输出＃1：

[{"title":"Fun","url":"fun/index.html","queries":["music","artists","events","internet"]},{"title":"Internet","url":"internet/index.html","queries":["javascript","web","internet"]}]

输入＃2：

getResult("music", yourObject);

输出＃2：

[{"title":"Fun","url":"fun/index.html","queries":["music","artists","events","internet"]}]

Answer 2

var search = function(data, query) {
    return data.hightlights.filter(function(highlight) {
        return highlight.queries.indexOf(query) > -1;
    });
}

search(data, "music");

如果您有curry功能可用（来自 Ramda ， Lo-Dash 等），您可以将其换行：

var search = curry(function(data, query) { ... });

然后您可以通过先传入数据来创建更简单的函数：

highlights = search(data);
//...
highlights("music"); //=> those containing "music"
highlights("internet"); //=> those containing "internet"

更新

我知道已有一个可行的解决方案。但这可能会有点简单。

这将在查询中搜索子词：

var search = function(data, query) {
    return data.hightlights.filter(function(highlight) {
        return highlight.queries.filter(function(q) {
            return q.indexOf(query) > -1;
        }).length > 0;
    });
}

Answer 3

var xyz = {
   "hightlights":[
      {
         "title":"Fun",
         "url":"fun/index.html",
         "queries":[
            "music",
            "artists",
            "events",
            "internet"
         ]
      },
      {
         "title":"Internet",
         "url":"internet/index.html",
         "queries":[
            "javascript",
            "web",
            "internet",
         ]
      }
   ]
}

不要说“var word”包含要搜索的关键字，那么你可以这样做：

var arr = [];
for(var i in xyz['highlights']){
        var queries = xyz['highlights']['queries'];
        for(j in queries){
              if (word == queries[j]){
                       arr.push(xyz['highlights'][i]);
                       continue;
              }
        }
}

arr应该有你需要的对象。对不起，这是非常基本的。但希望它有所帮助。

过滤嵌套的JSON javascript

3 个答案:

更新