Question

我的查询定义如下

select distinct
    to_number("Rental"."pkRentalId") "pkRentalId",
    to_char("Rental"."RentalNo") "RentalNo",
case when "RentedVehicle"."fkRegisteredVehicleId" is not null 
    then to_char("Vehicle"."RegistrationNumber")
    else to_char("TempVehicle"."RegistrationNumber") 
    end "VehicleRegNo"

from 
    "Rental"
    inner join "RentedVehicle" on "RentedVehicle"."fkRentalId"="Rental"."pkRentalId"
    left join "Vehicle" on "Vehicle"."pkVehicleId"="RentedVehicle"."fkRegisteredVehicleId"
    left join "TempVehicle" on "TempVehicle"."pkTempVehicleId"="RentedVehicle"."fkTempVehicleId"

我希望我的查询返回RentedVehicle From Rental

中保存的最后一辆车

租用的车辆有多辆车可以抵抗单一租赁。但我希望最后一个对抗租赁。

请帮助。

我想要

pkRentalId       RenatlNo            VehicleRegNo

1                  100002              KM123
2                  100003              KM123
3                  100004              LOP990
12                  100005              KM123
32                  100007              KM123
34                  100009              LOP990

- 表

"RentedVehicle" 
   (    "pkRentedVehicleId" NUMBER(19,0), 
    "fkRegisteredVehicleId" NUMBER(19,0), 
    "fkTempVehicleId" NUMBER(19,0), 
    "fkRentalId" NUMBER(19,0) NOT NULL ENABLE, 
    "fkOutBranchId" NUMBER(19,0) NOT NULL ENABLE, 
    "fkReturnBranchId" NUMBER(19,0) NOT NULL ENABLE, 
    "CheckOutFuel" NUMBER(19,0) NOT NULL ENABLE, 
    "CheckOutOdometer" NUMBER(19,0) NOT NULL ENABLE, 
    "CheckInFuel" NUMBER(19,0), 
    "CheckInOdometer" NUMBER(19,0), 
    "TransferPointFuel" NUMBER(19,0), 
    "TransferPointOdometer" NUMBER(19,0), 
    "TotalCustomerKilometer" NUMBER(19,0), 
    "fkExchangeId" NUMBER(19,0), 
    "IsDeleted" CHAR(1 BYTE) NOT NULL ENABLE, 
    "CreatedOn" DATE NOT NULL ENABLE, 
    "CreatedBy" NUMBER(19,0) NOT NULL ENABLE, 
    "LastUpdatedOn" DATE, 
    "LastUpdatedBy" NUMBER(19,0)
)

Rental" 
   (    "pkRentalId" NUMBER(19,0), 
    "RentalNo" VARCHAR2(15 BYTE) NOT NULL ENABLE, 
    "fkRentalStatusId" NUMBER(19,0) NOT NULL ENABLE, 
    "fkRateId" NUMBER(19,0) NOT NULL ENABLE, 
    "fkExtraId" NUMBER(19,0), 
    "fkBillingId" NUMBER(19,0), 
    "fkRateTypeId" NUMBER(19,0) NOT NULL ENABLE, 
    "fkDebtorId" NUMBER(19,0) NOT NULL ENABLE, 
    "fkSubDebtorId" NUMBER(19,0), 
    "fkBranchId" NUMBER(19,0) NOT NULL ENABLE, 
    "fkChangeTypeId" NUMBER(19,0) NOT NULL ENABLE, 
    "ChangeReason" VARCHAR2(255 BYTE), 
    "fkFromLocationId" NUMBER(19,0), 
    "fkToLocationId" NUMBER(19,0), 
    "fkCityId" NUMBER(19,0) NOT NULL ENABLE, 
    "CheckedOutOn" DATE NOT NULL ENABLE, 
    "ExpectedCheckInOn" DATE NOT NULL ENABLE, 
    "CheckedInOn" DATE, 
    "ReportingDateTime" DATE, 
    "ServiceInstructions" VARCHAR2(255 BYTE), 
    "DropOffRemarks" VARCHAR2(255 BYTE), 
    "IsDeleted" CHAR(1 BYTE) NOT NULL ENABLE, 
    "CreatedOn" DATE NOT NULL ENABLE, 
    "CreatedBy" NUMBER(19,0) NOT NULL ENABLE, 
    "LastUpdatedOn" DATE, 
    "LastUpdatedBy" NUMBER(19,0)
)

Answer 1

你可以尝试这件事我仍然不确定它和你的数据

select 
B.pkRentalId,
B.RentalNo,
B.VehicleRegNo
from
(
select 
A.pkRentalId,
A.RentalNo,
A.VehicleRegNo,
MAX(rn) 
from 
(select 
      to_number("Rental"."pkRentalId") "pkRentalId",
    to_char("Rental"."RentalNo") "RentalNo",
case when "RentedVehicle"."fkRegisteredVehicleId" is not null 
    then to_char("Vehicle"."RegistrationNumber")
    else to_char("TempVehicle"."RegistrationNumber") 
    end "VehicleRegNo",
    ROW_NUMBER() OVER(PARTITION BY "Rental"."pkRentalId" ORDER BY "Rental"."CheckedInOn") rn

from 
    "Rental"
    inner join "RentedVehicle" on "RentedVehicle"."fkRentalId"="Rental"."pkRentalId"
    left join "Vehicle" on "Vehicle"."pkVehicleId"="RentedVehicle"."fkRegisteredVehicleId"
    left join "TempVehicle" on "TempVehicle"."pkTempVehicleId"="RentedVehicle"."fkTempVehicleId"
)   
A
group by A.pkRentalId,
A.RentalNo,
A.VehicleRegNo
) 
B

这里我使用"Rental"."CheckedInOn"作为车辆日期，您可以根据它进行更改。

区分具有内连接和左连接的单个列来自3个不同的表oracle pl / sql

1 个答案: