通过名称动态传递参数

Question

是否可以动态设置传递给函数的参数名称？

像这样：

def func(one=None, two=None, three=None, four=None):
    ...

params = ("one","two","three","four",)
for var in params:
    tmp = func(var=value)

Answer 1

是的，keyword argument unpacking：

def func(one=None, two=None, three=None, four=None):
    return (one, two, three, four)

params = ("one", "two", "three", "four")
for var in params:
    tmp = func(**{var: "!!"})
    print(tmp)

输出：

('!!', None, None, None)
(None, '!!', None, None)
(None, None, '!!', None)
(None, None, None, '!!')