Question

我正在使用Oracle SQL Developer。源表中有一列fiscal_week_string，其格式如下：

2011 – 01 (09/27 – 10/31)

我想将其转换为以下格式：

2011-01 (09/27 to 10/31)

即，我想删除一些的空格。我还想用“-”替换大括号内的“to”。

以下是几行：

datestr pc WEEK_START WEEK_END month_start mnth_end year mth qtr wk fiscal_week_string Fiscal_month_string 2010-09-27 14879 2010-09-27 2010-10-03 2010-09-27 2010-10-31 2011 1 1 1 2011 – 01 (09/27 – 10/03) 2011 – 01 (09/27 – 10/31) 2010-09-28 14880 2010-09-27 2010-10-03 2010-09-27 2010-10-31 2011 1 1 1 2011 – 01 (09/27 – 10/03) 2011 – 01 (09/27 – 10/31)

有人可以指导我吗？

Answer 1

您可以使用regexp_replace替换目标模式。

示例：

    select regexp_replace(
    regexp_replace('2011 - 01 (09/27 - 10/31)',' - ','-',1,1)
     , ' - ',' to ') from dual;

样本更新：

create table a1(id number, name varchar2(100));
insert into a1 values(1, '2011 - 01 (09/27 - 10/31)');
update a1 set name=
regexp_replace(regexp_replace(name,' - ','-',1,1), ' - ',' to ') where id=1;
select * from a1;

Answer 2

由于您尚未共享DDL，因此期望DDL

create table table_one
(
fiscal_week_string varchar(30)
);

insert into table_one
values ('2011 – 01 (09/27 – 10/31)');

insert into table_one
values ('2011 – 01 (09/26 – 11/31)');

您的Oracle查询将是

select col_one || col_two || col_three || ' ' || col_four||' '|| 'to'||' '||col_six as fmt_date
from
(
select REGEXP_SUBSTR(t.fiscal_week_string, '[^ ]+', 1, 1) col_one,
REGEXP_SUBSTR(t.fiscal_week_string, '[^ ]+', 1, 2) col_two,
REGEXP_SUBSTR(t.fiscal_week_string, '[^ ]+', 1, 3) col_three,
REGEXP_SUBSTR(t.fiscal_week_string, '[^ ]+', 1, 4) col_four,
REGEXP_SUBSTR(t.fiscal_week_string, '[^ ]+', 1, 5) col_five,
REGEXP_SUBSTR(t.fiscal_week_string, '[^ ]+', 1, 6) col_six
from table_one t
)

和

结果

2011–01 (09/27 to 10/31) 
2011–01 (09/26 to 11/31)

SQL小提琴http://sqlfiddle.com/#!4/c30b15/8

Answer 3

DECLARE @str varchar(50)='2011 – 01 (09/27 – 10/31)'

SELECT REPLACE(SUBSTRING(@str, 0,CHARINDEX('(',@str)),' ','')+' '+ REPLACE(SUBSTRING(@str,CHARINDEX('(',@str),len(@str)),'–','to')

替换字符串中特定位置的特定字符

3 个答案: