SQL加入后返回更多行

时间：2014-12-18 01:05:55

标签： sql sql-server oracle join oracle11g

我正在尝试使用以下数据加入2个表。当我使用下面的查询加入时，它会获得多个重复的行。我使用了不同的。

提前道歉，说明帖子不正确或不充分。请耐心等待，因为这是我第一次在这个论坛上发帖提问。

我正在使用以下查询。

select a.timestamp_for_start_message, b.timestamp_for_start_message 
from start_message a, success_message b where a.id1 = b.id1 and a.jobid = b.jobid;
启动消息表 
ID1     Timestamp_start_msg_recieved    date        jobid      message
1234    5/14/2014 10:02:29              5/14/2014   abc        start
1234    5/14/2014 10:02:29              5/14/2014   abc        start
1234    5/14/2014 10:02:29              5/14/2014   abc        start
1234    5/14/2014 10:02:29              5/14/2014   abc        start
1234    5/14/2014 10:09:06              5/14/2014   abc        start
1234    5/14/2014 10:09:06              5/14/2014   abc        start
1234    5/14/2014 10:09:06              5/14/2014   abc        start
1234    5/14/2014 10:09:06              5/14/2014   abc        start
1234    5/14/2014 11:45:11              5/14/2014   abc        start
1234    5/14/2014 11:45:11              5/14/2014   abc        start
1234    5/14/2014 11:45:11              5/14/2014   abc        start
1234    5/14/2014 11:45:11              5/14/2014   abc        start
1234    5/14/2014 19:02:52              5/14/2014   abc        start
5678    5/14/2014 22:02:52              5/14/2014   pqr        start
5678    5/14/2014 23:10:40              5/14/2014   pqr        start
成功消息表 
ID1     Timestamp_success_msg_recieved  date        jobid  message
1234    5/14/2014 10:02:31              5/14/2014   abc    successful
1234    5/14/2014 10:02:31              5/14/2014   abc    successful
1234    5/14/2014 10:02:31              5/14/2014   abc    successful
1234    5/14/2014 10:02:31              5/14/2014   abc    successful
1234    5/14/2014 10:09:10              5/14/2014   abc    successful
1234    5/14/2014 10:09:10              5/14/2014   abc    successful
1234    5/14/2014 10:09:10              5/14/2014   abc    successful
1234    5/14/2014 10:09:10              5/14/2014   abc    successful
1234    5/14/2014 16:48:22              5/14/2014   abc    successful
1234    5/14/2014 19:03:00              5/14/2014   abc    successful
5678    5/14/2014 22:03:00              5/14/2014   pqr    successful

我试图在这两个表的时间戳之间得到最接近的匹配。 以下是另一种查看数据的方法。 要满足的条件：一个启动消息可以具有多个成功消息，其具有相同或不同的时间戳，用于相同的id和jobid。我需要选择最大开始消息到成功消息的最小消息，以使其匹配。

id      Time_stamp_message_recieved  message      jobid
1234    5/14/2014 10:02:29           started      abc
1234    5/14/2014 10:02:29           started      abc
1234    5/14/2014 10:02:29           started      abc
1234    5/14/2014 10:02:29           started      abc
1234    5/14/2014 10:02:31           successful   abc
1234    5/14/2014 10:02:31           successful   abc
1234    5/14/2014 10:02:31           successful   abc
1234    5/14/2014 10:02:31           successful   abc
1234    5/14/2014 10:09:06           started      abc
1234    5/14/2014 10:09:06           started      abc
1234    5/14/2014 10:09:06           started      abc
1234    5/14/2014 10:09:06           started      abc
1234    5/14/2014 10:09:10           successful   abc
1234    5/14/2014 10:09:10           successful   abc
1234    5/14/2014 10:09:10           successful   abc
1234    5/14/2014 10:09:10           successful   abc
1234    5/14/2014 11:45:11           started      abc
1234    5/14/2014 11:45:11           started      abc
1234    5/14/2014 11:45:11           started      abc
1234    5/14/2014 11:45:11           started      abc
1234    5/14/2014 16:48:22           successful   abc
1234    5/14/2014 19:02:52           started      abc
1234    5/14/2014 19:03:00           successful   abc

PS：我正在基于两个表中的ID和JOBID以及TIMESTAMP进行排序，然后根据ID和JOBID加入。

预期结果

ID1  IMESTAMP_for_start_message TIMESTAMP_for_start_message  Date       Jobid    start_message
1234 5/14/2014 10:02:29         5/14/2014 10:02:31           5/14/2014  abc
1234 5/14/2014 10:09:06         5/14/2014 10:09:10           5/14/2014  abc
1234 5/14/2014 11:45:11         5/14/2014 16:48:22           5/14/2014  abc
1234 5/14/2014 19:02:52         5/14/2014 19:03:00           5/14/2014  abc
5678 5/14/2014 22:02:52         5/14/2014 22:03:00           5/14/2014  pqr
5678 5/14/2014 23:10:40         null                         5/14/2014  pqr

**********************以下编辑问题********************** *******

假设我说下面提到的数据，我希望得到最大的开始消息和相应的最小或成功消息。

启动消息表 
ID1     Timestamp_start_msg_recieved    date        jobid      message
1234    5/14/2014 10:02:29              5/14/2014   abc        start
1234    5/14/2014 10:02:31              5/14/2014   abc        start
1234    5/14/2014 10:02:45              5/14/2014   abc        start
1234    5/14/2014 10:02:50              5/14/2014   abc        start
1234    5/14/2014 10:09:04              5/14/2014   abc        start
1234    5/14/2014 10:09:06              5/14/2014   abc        start
1234    5/14/2014 10:09:16              5/14/2014   abc        start
1234    5/14/2014 10:09:26              5/14/2014   abc        start
1234    5/14/2014 11:45:11              5/14/2014   abc        start
1234    5/14/2014 16:48:20              5/14/2014   abc        start
1234    5/14/2014 19:02:52              5/14/2014   abc        start
5678    5/14/2014 22:02:52              5/14/2014   pqr        start
5678    5/14/2014 23:10:40              5/14/2014   pqr        start
成功消息表 
ID1     Timestamp_success_msg_recieved  date        jobid  message
1234    5/14/2014 10:02:52              5/14/2014   abc    successful
1234    5/14/2014 10:09:32              5/14/2014   abc    successful
1234    5/14/2014 11:45:15              5/14/2014   abc    successful
1234    5/14/2014 11:45:18              5/14/2014   abc    successful
1234    5/14/2014 11:45:19              5/14/2014   abc    successful
1234    5/14/2014 11:45:25              5/14/2014   abc    successful
1234    5/14/2014 16:48:22              5/14/2014   abc    successful
1234    5/14/2014 19:03:00              5/14/2014   abc    successful
5678    5/14/2014 22:03:00              5/14/2014   pqr    successful

预期结果

ID1  IMESTAMP_for_start_message TIMESTAMP_for_start_message  Date       Jobid    msg  msg
1234 5/14/2014 10:02:50         5/14/2014 10:02:52           5/14/2014  abc start success
1234 5/14/2014 10:09:26         5/14/2014 10:09:32           5/14/2014  abc start success
1234 5/14/2014 11:45:11         5/14/2014 11:45:25           5/14/2014  abc start success
1234 5/14/2014 16:48:20         5/14/2014 16:48:22           5/14/2014  abc start success
1234 5/14/2014 19:02:52         5/14/2014 19:03:00           5/14/2014  abc start success
5678 5/14/2014 22:02:52         5/14/2014 22:03:00           5/14/2014  pqr start success
5678 5/14/2014 23:10:40         null                         5/14/2014  pqr start success

我正在寻找Max of start的消息与成功的消息配对。

我试图在这两个表的时间戳之间得到最接近的匹配。 以下是另一种查看数据的方法。 要满足的条件：一个启动消息可以具有多个成功消息，其具有相同或不同的时间戳，用于相同的id和jobid。我需要选择最大开始消息到成功消息的最小消息，以使其匹配。

id      Time_stamp_message_recieved  message      jobid
1234    5/14/2014 10:02:29           started      abc
1234    5/14/2014 10:02:29           started      abc
1234    5/14/2014 10:02:29           started      abc
1234    5/14/2014 10:02:29           started      abc
1234    5/14/2014 10:02:31           successful   abc
1234    5/14/2014 10:02:31           successful   abc
1234    5/14/2014 10:02:31           successful   abc
1234    5/14/2014 10:02:31           successful   abc
1234    5/14/2014 10:09:06           started      abc
1234    5/14/2014 10:09:06           started      abc
1234    5/14/2014 10:09:06           started      abc
1234    5/14/2014 10:09:06           started      abc
1234    5/14/2014 10:09:10           successful   abc
1234    5/14/2014 10:09:10           successful   abc
1234    5/14/2014 10:09:10           successful   abc
1234    5/14/2014 10:09:10           successful   abc
1234    5/14/2014 11:45:11           started      abc
1234    5/14/2014 11:45:11           started      abc
1234    5/14/2014 11:45:11           started      abc
1234    5/14/2014 11:45:11           started      abc
1234    5/14/2014 16:48:22           successful   abc
1234    5/14/2014 19:02:52           started      abc
1234    5/14/2014 19:03:00           successful   abc

2 个答案:

答案 0 :(得分：0)

您的查询是：

select a.timestamp_for_start_message, b.timestamp_for_start_message
from start_message a join
     success_message b
where a.id1 = b.id1 and a.jobid = b.jobid;

当然这会产生重复。示例数据中的每一行都具有id和jobid的相同值。

时间戳似乎也是一个连接键。你似乎在寻找平等，所以你可以这样做：

select a.timestamp_for_start_message, b.timestamp_for_start_message
from start_message a join
     success_message b
where a.id1 = b.id1 and a.jobid = b.jobid and
      a.TIMESTAMP_for_start_message = b.TIMESTAMP_for_success_message

答案 1 :(得分：0)

使用最新的样本数据，显然仍然可以达到目的：

SELECT
  DISTINCT
  StMT.id1
  , TIMESTAMP_for_start_message
  , (SELECT MIN(TIMESTAMP_for_success_message)
     FROM SuccessMessageTable
     WHERE
       (id1 = StMT.id1)
       AND (someDate = StMT.someDate)
       AND (jobID = StMT.jobID)
       AND (TIMESTAMP_for_success_message >= StMT.TIMESTAMP_for_start_message)) TIMESTAMP_for_success_message
  , StMT.someDate
  , StMT.jobID
  , NULL start_message
FROM StartMessageTable StMT
ORDER BY id1, jobID, TIMESTAMP_for_start_message;

SQL Fiddle

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