Question

我制作简易版的扫雷并且对这部分代码有疑问：

if ((uncover == 0) && inGame) {
        inGame = false;
        long elapsedTime = (System.currentTimeMillis() - start)/1000;
        JOptionPane.showInputDialog(null, "Congrats, you won! \n Your result is "
                + elapsedTime + " sec. Please, enter your name: ");
        statusbar.setText("Game won");
        }
    else if (!inGame)
        statusbar.setText("Game lost");

所以这就是事情：如果游戏获胜，它会显示输入对话框，但状态栏仍然会变为＆＃34;游戏丢失＆＃34;。如果我删除或评论此

JOptionPane.showInputDialog(null, "Congrats, you won! \n Your result is "
                + elapsedTime + " sec. Please, enter your name: ");

一切正常。问题是什么？

Answer 1

您需要捕获输入，并且您没有填写所有可能导致警告或编译错误的inputdialog选项。

String getInput = "";
getInput = (String)JOptionPane.showInputDialog(
        null,
        "Congrats, you won! \n Your result is "
            + elapsedTime + " sec. Please, enter your name: ",
        null,
        JOptionPane.PLAIN_MESSAGE,
        null,
        null,
        null);

希望这有帮助

showInputDialog使“if”工作错误

1 个答案: