我需要修改代码，以便
我的新代码位于底部，但它尚未正常工作，无法弄明白我还需要做些什么。如果有人可以提供帮助，那就可以了。
import java.util.Scanner;
public class MakeMeBetter
{
public static void main(String[] args)
{
int[] a = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
Scanner b = new Scanner(System.in);
System.out.println("Please input 10 numbers in the range 1-19 :> ");
int c = b.nextInt();
while (c < 1 || c > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[0] = c;
int d = b.nextInt();
while (d < 1 || d > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[1] = d;
int e = b.nextInt();
while (e < 1 || e > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[2] = e;
int f = b.nextInt();
while (f < 1 || f > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[3] = f;
int g = b.nextInt();
while (g < 1 || g > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[4] = g;
int h = b.nextInt();
while (h < 1 || h > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[5] = h;
int i = b.nextInt();
while (i < 1 || i > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[6] = i;
int j = b.nextInt();
while (j < 1 || j > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[7] = j;
int k = b.nextInt();
while (k < 1 || k > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[8] = k;
int l = b.nextInt();
while (l < 1 || l > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
}
a[9] = l;
System.out.println("\nArray contents");
System.out.print((a[0] < 10 ? " " : "") + a[0] + " ");
System.out.print((a[1] < 10 ? " " : "") + a[1] + " ");
System.out.print((a[2] < 10 ? " " : "") + a[2] + " ");
System.out.print((a[3] < 10 ? " " : "") + a[3] + " ");
System.out.print((a[4] < 10 ? " " : "") + a[4] + " ");
System.out.print((a[5] < 10 ? " " : "") + a[5] + " ");
System.out.print((a[6] < 10 ? " " : "") + a[6] + " ");
System.out.print((a[7] < 10 ? " " : "") + a[7] + " ");
System.out.print((a[8] < 10 ? " " : "") + a[8] + " ");
System.out.print((a[9] < 10 ? " " : "") + a[9] + " ");
System.out.println();
boolean noSwap = false;
int startAt = 0;
int stopAt = 9;
while (startAt < stopAt && noSwap == false)
{
noSwap = true;
for (int m=startAt; m<stopAt; m++)
{
if (a[m] > a[m+1])
{
int t = a[m];
a[m] = a[m+1];
a[m+1] = t;
noSwap = false;
}
}
stopAt = stopAt - 1;
}
System.out.println("\nArray contents");
System.out.print((a[0] < 10 ? " " : "") + a[0] + " ");
System.out.print((a[1] < 10 ? " " : "") + a[1] + " ");
System.out.print((a[2] < 10 ? " " : "") + a[2] + " ");
System.out.print((a[3] < 10 ? " " : "") + a[3] + " ");
System.out.print((a[4] < 10 ? " " : "") + a[4] + " ");
System.out.print((a[5] < 10 ? " " : "") + a[5] + " ");
System.out.print((a[6] < 10 ? " " : "") + a[6] + " ");
System.out.print((a[7] < 10 ? " " : "") + a[7] + " ");
System.out.print((a[8] < 10 ? " " : "") + a[8] + " ");
System.out.print((a[9] < 10 ? " " : "") + a[9] + " ");
System.out.println();
double n = (a[0] + a[1] + a[2] + a[3] +
a[4] + a[5] + a[6] + a[7] +
a[8] + a[9]) / 10;
System.out.println("The minimum number is: " + a[0]);
System.out.println("The maximum number is: " + a[9]);
System.out.println("The average value is: " + n);
System.out.println("The median is: " + a[4]);
}
}
import java.util.Scanner;
import java.math.*;
public class MakeMeBetterImproved {
public static void main(String[] args) {
Scanner kybd = new Scanner(System.in);
int[] numbers = new int[10];
int array = 0;
System.out.println("Enter 10 integers: ");
for (int i = 0; i < numbers.length; i++) {
numbers[i] = kybd.nextInt();
int MyIntArray = array + i;
}
System.out.println("The minimum number is: " + math.min);
System.out.println("The maximum number is: " + math.max);
System.out.println("The average value is: " + math.average);
System.out.println("The median is: " + math.median);
}
}
答案 0 :(得分：0)
考虑使用比原始数组更动态的结构。
我喜欢ArrayLists：http://docs.oracle.com/javase/7/docs/api/java/util/ArrayList.html
将长代码重新组织为while或for循环。
一个例子：
ArrayList<Integer> a = new ArrayList<Integer>();
Scanner b = new Scanner(System.in);
Integer c = null;
while (a.size() != 10) {
System.out.println("Please input a number in the range 1-19 :> ");
c = b.nextInt();
while (c < 1 || c > 19)
{
System.out.println("Not in the range 1-19, please try again :> ");
c = b.nextInt();
}
a.add(c);
}
System.out.println("\nArray contents");
for (int i=0; i<10; i++) {
System.out.print((a.get(i) < 10 ? " " : "") + a.get(i) + " ");
}
（等等......）
答案 1 :(得分：0)
package p2;
import java.util.Arrays;
import java.util.Scanner;
public class TicTacToe {
public static void main(String[] args) {
Scanner kybd = new Scanner(System.in);
int[] numbers = new int[10];
int sum = 0;
System.out.println("Enter 10 integers: ");
for (int i = 0; i < numbers.length; i++) {
numbers[i] = kybd.nextInt();
sum += numbers[i];
}
Arrays.sort(numbers);
System.out.println("The minimum number is: " + numbers[0]);
System.out.println("The maximum number is: " + numbers[9]);
System.out.println("The average value is: " + sum / numbers.length);
System.out.println("The median is: " + median(numbers));
}
public static double median(int[] m) {
int middle = m.length / 2;
if (m.length % 2 == 1) {
return m[middle];
} else {
return (m[middle - 1] + m[middle]) / 2.0;
}
}
}