jQuery链接和级联然后是什么时候

Question

我目前在我面前有一个非常棒的if-then-else循环，首先从网络服务获得多个cantinas。然后它会获得所有可用餐点（每个菜单）和所有可用的配菜（每个菜单）。对于每一餐和两餐，然后检查所有添加剂并聚集它们。

最后我有多种菜单，包括餐点，配菜和所有添加剂。

以下流程图显示了该过程：

我想美化代码并希望利用jQuery的promises - 但我无法弄清楚如何做到这一点，因为我必须在then之后堆叠when（at至少我想，也许我必须resolve？）。以下是我最好的尝试：

//this totally does not work at all, but you get the idea what I want to do
Menus.getCantinas()
       .when(Menus.getMeals(cantinas), Menus.getSides(cantinas)) //when doesn't exist here, neither does cantinas
         .then(Menus.getAdditives(meals, sides) //also throws errors as meals and sides does not exist
           .done(function(cantinas, meals, sides, additives) { //more errors for the people
             Menus.cantinas = cantinas;
             Menus.meals = meals;
             Menus.sides = sides;
             Menus.additives = additives;

             //... some html stuff to build the menus
           });

请务必查看以下代码段以获取更多解释性代码。

window.Menus = {
	cantinas = {},
	meals = {},
	sides = {},
	additives = {},
	callWebservice: function (listname, filter)
    {
        if (filter && filter != '')
            data['$filter'] = filter;

        return jQuery.ajax({
            url: '/_api/web/lists/getbytitle(\'' + listname + '\')/items',
            data: data,
            dataType: 'json'
        });
    },

	getCantinas: function() {
		return Menus.callWebservice("Cantinas", "");
	},
	
	getMeals: function(cantinas) {
		var filterString;
		for (var i = 0; i < cantinas.length; i++) {
			if (i == 0) {
				filterstring = "ID eq " + cantinas[i];
			}
			else {
				filterstring += " or ID eq " + cantinas[i]
			}
		}
		return Menus.callWebservice("Meals", filterString);
	},
	
	
	getSides: function(cantinas) {
		//see above function for filterstuff
		return Menus.callWebservice("Sides", filterString);
	},
	
	getAdditives: function(meals, sides) {
		for (var i = 0; i < meals.length; i++) {
			if (i == 0 && !meals) {
				filterstring = "ID eq " + meals[i];
			}
			else {
				filterstring += " or ID eq " + meals[i]
			}
		}
		
		for (var i = 0; i < sides.length; i++) {
			if (i == 0 && !sides) {
				filterstring = "ID eq " + sides[i];
			}
			else {
				filterstring += " or ID eq " + sides[i]
			}
		}
		return Menus.callWebservice("Additives", "");
	}
	Init: function() {
		//this totally does not work at all, but you get the idea what I want to do
		Menus.getCantinas()
			   .when(Menus.getMeals(cantinas), Menus.getSides(cantinas))
			     .then(Menus.getAdditives(meals, sides)
			       .done(function(cantinas, meals, sides, additives){
				     Menus.cantinas = cantinas;
					 Menus.meals = meals;
					 Menus.sides = sides;
					 Menus.additives = additives;
					 
					 //... some html stuff to build the menus
				   });
	}
}
Menus.Init()

我希望我有意义吗？如何使用承诺和级联参数从一个到另一个，基本上如何使上述声明工作，让我的多个菜单与多餐，边和添加剂。

Answer 1

与评论一样，$.when是免费功能。如果我们使用then能够链接，我们可以在这里获得非常干净的语法。

Menus.getCantinas().then(function(cantinas){ // `then` is how we chain promises
    Menus.cantinas = cantinas;
    // if we need to aggregate more than one promise, we `$.when`
    return $.when(Menus.getMeals(cantinas), Menus.getSides(cantinas));
}).then(function(meals, sides){ // in jQuery `then` can take multiple arguments
    Menus.sides = sides; // we can fill closure arguments here
    Menus.meals = meals;
    return Menus.getAdditives(meals, sides); // again we chain
}).then(function(additives){
    Menus.additives = additives;
    return Menus; // we can also return non promises and chain on them if we want
}).done(function(){ // done terminates a chain generally.
     // edit HTML here
});