我正在尝试从用户个人资料中获取一些数据,但它找不到该列。我已经检查了每个查询之间的空间,似乎没有错。直到现在我看不出问题,任何想法?谢谢你 这是我的代码和错误消息
表名
private static final String TABLE_PROFILE = "users";
private static final String TABLE_STATUS = "status";
用户列名
//Users column names
private static final String KEY_USER_ID = "user_id";
private static final String KEY_USER_IMG = "picture";
private static final String KEY_USER_EMAIL = "email";
private static final String KEY_USER_NAME = "name";
private static final String KEY_USER_PASSWORD = "password";
private static final String KEY_USER_PHONE = "phone";
状态列名称
//Status column names
private static final String KEY_STATUS_ID = "status_id";
private static final String KEY_STATUS = "status";
表创建声明
//Users table create statement
private static final String CREATE_TABLE_PROFILE = "CREATE TABLE " + TABLE_PROFILE +
"(" + KEY_USER_ID + " INTEGER PRIMARY KEY," + KEY_USER_IMG + " BLOB," +
KEY_USER_EMAIL + " VARCHAR," + KEY_USER_NAME + " VARCHAR," + KEY_USER_PASSWORD + " VARCHAR,"
+ KEY_USER_PHONE + " VARCHAR," + KEY_CREATED_AT + " DATETIME," + KEY_STATUS_ID + " INTEGER,"
+ " FOREIGN KEY " + "(" + KEY_STATUS_ID + ")" + " REFERENCES " + TABLE_STATUS + "(" + KEY_STATUS_ID + ")" + ")";
getProfile方法
public Profile getProfile(String username){
SQLiteDatabase db = this.getReadableDatabase();
String selectQuery = "SELECT * FROM " + TABLE_PROFILE + " WHERE " + KEY_USER_EMAIL + " = " + username;
Log.e(LOG, selectQuery);
Cursor c = db.rawQuery(selectQuery, null);
if(c!=null)
c.moveToFirst();
Profile pf = new Profile();
pf.setID(c.getInt(c.getColumnIndex(KEY_USER_ID)));
pf.setImg(c.getBlob(c.getColumnIndex(KEY_USER_IMG)));
pf.setEmail(c.getString(c.getColumnIndex(KEY_USER_EMAIL)));
pf.setName(c.getString(c.getColumnIndex(KEY_USER_NAME)));
pf.setPassword(c.getString(c.getColumnIndex(KEY_USER_PASSWORD)));
pf.setPhone(c.getString(c.getColumnIndex(KEY_USER_PHONE)));
pf.setCreatedAt(c.getString(c.getColumnIndex(KEY_CREATED_AT)));
return pf;
}
logcat消息
12-18 02:50:32.616: E/DatabaseHelper(7093): SELECT * FROM users WHERE email = test1
12-18 02:50:32.616: E/SQLiteLog(7093): (1) no such column: test1
12-18 02:50:32.636: E/AndroidRuntime(7093): FATAL EXCEPTION: main
12-18 02:50:32.636: E/AndroidRuntime(7093): android.database.sqlite.SQLiteException: no such column: test1 (code 1): , while compiling: SELECT * FROM users WHERE email = test1
答案 0 :(得分:1)
在SQL中,必须引用字符串文字。
但是,为避免格式化此类问题(以及SQL注入攻击),请改用parameters:
Cursor c = db.rawQuery("SELECT * FROM " + TABLE_PROFILE +
" WHERE " + KEY_USER_EMAIL + " = ?",
new String[]{ username });
答案 1 :(得分:0)
KEY_USER_EMAIL列不是字符串类型吗?如果是这样的话,你的where子句WHERE" + KEY_USER_EMAIL +" =" +用户名 试图将列值称为KEY_USER_EMAIL = test1,而它应该真正引用/使用它,
KEY_USER_EMAIL =' test1' 只需将您的Where子句更改为这样 -
SELECT * FROM " + TABLE_PROFILE + " WHERE " + KEY_USER_EMAIL + " = '" + username + "'"
答案 2 :(得分:0)
使用此
String selectQuery = "SELECT * FROM " + TABLE_PROFILE + " WHERE " + KEY_USER_EMAIL + " = " + "'" + username + "'";
用户名的值需要作为字符串传递。