Question

我有两个包含工作人员的阵列。一个数组包含酒店的所有工作人员作为Staff个对象，另一个数组仅包含当前作为Staff个对象工作的工作人员。

我有一个自定义对象;

Staff.h

NSString * staff_id;
NSString * staff_name;
BOOL isWorking

我的最后一个数组是包含所有工作人员，每个工作人员只有一个实例（所以每个工作人员只在数组中出现一次）和Staff个对象的BOOL值设置为{{1}工作人员在哪里工作。默认情况下，NO/FALSE/0设置为TRUE。

我尝试了不同条件语句的组合，但我仍然得到重复。我的条件陈述绝对不是最佳的。我试图最大限度地开始使用更加优化的解决方案。

isWorking

我一直在寻求改进，所以欢迎任何有用的想法和建设性的批评。

目前的结果是-(void)sortStaff{ NSMutableArray * fullArray = [NSMutableArray array];//contain full array of staff objects NSMutableArray * idArray = [NSMutableArray array];//contain all staff ids in order to check whether they already exist in the array or not NSMutableArray * noDuplicatesArray = [NSMutableArray array];//the array to hold no duplicates //loop through all staff working for (int i =1; i<self.workingStaffArray.count; i++) { Staff * workingStaffMember = [[Staff alloc] init]; workingStaffMember = [self.workingStaffArray objectAtIndex:i]; //loop through all the staff of the hotel for (int j=0; j<self.allStaffArray.count; j++) { Staff * allStaffMember =[[Staff alloc] init]; allStaffMember=[self.allStaffArray objectAtIndex:j]; //if the workingStaffMember id is not equal to the allStaffMember id then they are not working today at the hotel if ([workingStaffMember.staff_id intValue] != [allStaffMember.staff_id intValue ]) { //set boolean to NO - they are not working today allStaffMember.isWorking=NO; //add the staff id to idArray [idArray addObject:allStaffMember.staff_id]; //loop through the objs for (NSString * obj in idArray) { //add the staff id to the noDuplicatesArray if it already exists if (![noDuplicatesArray containsObject:obj]) { [noDuplicatesArray addObject: obj]; //if it doesnt already exist in the noduplicatesArray it means we have not passed it already, add the staff object to the fullArray [fullArray addObject:allStaffMember]; } } } } } //The final array that already contains the working staff members, but the staff who are not working today are to be added to the end. [self.workingStaffArray addObjectsFromArray:fullArray]; }包含了今天所有工作人员以及在酒店工作的所有工作人员。

这一行;

self.workingStaffArray

让我失望，但欢迎提供更好的解决方案。

提前致谢：）

编辑：问题似乎是因为if ([workingStaffMember.staff_id intValue] != [allStaffMember.staff_id intValue ])有一个实例，每个工作人员都会被添加。例如，我希望结果基于以下示例;

loop through all staff

所有Staff数组包含（使用默认BOOL）;

Working array contains:

Staff{
staff_name = @"Charlie";
staff_id = @"121"
isWorking= YES;
}
Staff{
staff_name = @"Sam";
staff_id = @"122"
isWorking= YES;
}
Staff{
staff_name = @"BEN";
staff_id = @"124"
isWorking= YES;
}

finalArray看起来像这样：

Staff{
staff_name = @"Charlie";
staff_id = @"121"
isWorking= YES;
}
Staff{
staff_name = @"Sam";
staff_id = @"122"
isWorking= YES;
}
Staff{
staff_name = @"BEN";
staff_id = @"123"
isWorking= YES;
}
Staff{
staff_name = @"PETER";
staff_id = @"124"
isWorking= YES;
}
Staff{
staff_name = @"Louis";
staff_id = @"125"
isWorking= YES;
}

但目前的实施情况给出了：

Staff{
staff_name = @"Charlie";
staff_id = @"121"
isWorking= YES;
}
Staff{
staff_name = @"Sam";
staff_id = @"122"
isWorking= YES;
}
Staff{
staff_name = @"BEN";
staff_id = @"123"
isWorking= YES;
}
Staff{
staff_name = @"PETER";
staff_id = @"124"
isWorking= NO;
}
Staff{
staff_name = @"Louis";
staff_id = @"125"
isWorking= NO;
}

* EDIT2 * 我的结果不正确。只是为了清楚，以防万一很难理解：我有两个数组。一个包含今天工作的员工，一个包含酒店的所有员工。我想将两者合并为一个Staff对象数组。这个数组包含了今天工作的所有员工，以及那些今天不工作的员工。第三个数组将包含所有工作人员，但唯一的区别是他们将具有适当的BOOl值Staff{ staff_name = @"Charlie"; staff_id = @"121" isWorking= YES; } Staff{ staff_name = @"Sam"; staff_id = @"122" isWorking= YES; } Staff{ staff_name = @"BEN"; staff_id = @"123" isWorking= YES; } Staff{ staff_name = @"Charlie"; staff_id = @"121" isWorking= NO; } Staff{ staff_name = @"Sam"; staff_id = @"122" isWorking= NO; } Staff{ staff_name = @"BEN"; staff_id = @"123" isWorking= NO; } Staff{ staff_name = @"PETER"; staff_id = @"124" isWorking= NO; } Staff{ staff_name = @"Louis"; staff_id = @"125" isWorking= NO; }

Answer 1

首先实现isEqual对象的Staff方法：

- (BOOL)isEqual:(id)object
{
    if (![object isKindOfClass:[Staff class]])
        return NO;
    Staff *other = (Staff *)object;
    return self.staff_id == other.staff_id;
}

其次使用NSMutableSet来确保您拥有一组唯一的对象：

NSMutableSet *staffSet = [NSMutableSet new];
....
[staffSet addObject:obj];

（我认为这涵盖了您问题中的大多数问题;如果没有，请添加评论）。

数组排序 - 两个人员数组分为一个人员阵列，没有重复

1 个答案: