我想使用对话框显示两个数字选择器

Question

我试图在仅使用java的对话框上显示两个数字选择器，代码正常工作，但我无法以相等的宽度排列它。

这是我的代码

RelativeLayout relative = new RelativeLayout(mContext);
final NumberPicker aNumberPicker = new NumberPicker(mContext);
aNumberPicker.setMaxValue(50);
aNumberPicker.setMinValue(1);
final NumberPicker aNumberPickerA = new NumberPicker(mContext);
aNumberPickerA.setMaxValue(11);
aNumberPickerA.setMinValue(1);
aNumberPickerA.setDisplayedValues(new String[] { "Tea Cup", "Glass","Plate","Small Plate","Cutlets","Medium","Piece","Katori","Balls","Serving","egg"});

RelativeLayout.LayoutParams params = new RelativeLayout.LayoutParams(50, 50);

RelativeLayout.LayoutParams numPicerParams = new RelativeLayout.LayoutParams(RelativeLayout.LayoutParams.WRAP_CONTENT, RelativeLayout.LayoutParams.WRAP_CONTENT);
RelativeLayout.LayoutParams qPicerParams = new RelativeLayout.LayoutParams(RelativeLayout.LayoutParams.WRAP_CONTENT, RelativeLayout.LayoutParams.WRAP_CONTENT);


numPicerParams.addRule(RelativeLayout.CENTER_IN_PARENT);
qPicerParams.addRule(RelativeLayout.ALIGN_PARENT_RIGHT);
relative.setLayoutParams(params);
relative.addView(aNumberPicker,numPicerParams);
relative.addView(aNumberPickerA,qPicerParams);


AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(mContext);
alertDialogBuilder.setTitle("Select the number");
alertDialogBuilder.setView(relative);
alertDialogBuilder
        .setCancelable(false)
        .setPositiveButton("Ok",
            new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog,
                    int id) {
                Log.e("","New Quantity Value : "+ aNumberPicker.getValue());

            }
        })
        .setNegativeButton("Cancel",
            new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog,
                    int id) {
                dialog.cancel();
            }
        });
AlertDialog alertDialog = alertDialogBuilder.create();
alertDialog.show();

我希望将它们对齐等宽。

快照

Answer 1

您要在添加到 LinearLayout 的视图上设置 RelativeLayout.LayoutParams 。您应该使用 RelativeLayout 代替 LinearLayout 作为 NumberPicker 的父级。设置 RelativeLayout.LayoutParams 不会对 LinearLayout 起作用。

编辑：

我会使用LinearLayout作为父级，设置方向为水平，子级权重为＆＃39; 1＆＃39;。这将是这样的......

LinearLayout LL = new LinearLayout(mContext);
LL.setOrientation(LinearLayout.HORIZONTAL);
//
final NumberPicker aNumberPicker = new NumberPicker(mContext);
aNumberPicker.setMaxValue(50);
aNumberPicker.setMinValue(1);
//
final NumberPicker aNumberPickerA = new NumberPicker(mContext);
aNumberPickerA.setMaxValue(11);
aNumberPickerA.setMinValue(1);
aNumberPickerA.setDisplayedValues(new String[] { "Tea Cup", "Glass","Plate","Small Plate","Cutlets","Medium","Piece","Katori","Balls","Serving","egg"});
//
LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(50, 50);
params.gravity = Gravity.CENTER;
//
LinearLayout.LayoutParams numPicerParams = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
numPicerParams.weight = 1;
//
LinearLayout.LayoutParams qPicerParams = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
qPicerParams.weight = 1;
//
LL.setLayoutParams(params);
LL.addView(aNumberPicker,numPicerParams);
LL.addView(aNumberPickerA,qPicerParams);

我希望这会有所帮助。

祝你好运。 ：）