Question

我有这种情况：

我的字符串：

Try a lot of match groups

[COD_BODY="AZI_DIP-ANAG_AZI", LABEL="Apri link1"] come on Taranto

[ COD_BODY="AZI_DIP-ANAG_AZI", LABEL="Apri link2"]

[ COD_BODY ="AZI_DIP-ANAG_AZI", LABEL="Apri link3"]

[ COD_BODY = "AZI_DIP-ANAG_AZI", LABEL="Apri link4"]

[ COD_BODY = "AZI_DIP-ANAG_AZI", LABEL ="Apri link5"]

[ COD_BODY = "AZI_DIP-ANAG_AZI", LABEL = "Apri link6"]

[ COD_BODY = "AZI_DIP-ANAG_AZI" , LABEL = "Apri link5" ]

我已经写过这个面具（用Java编写）：

"(\\[(\\s*)\\bCOD_BODY(\\s*)=(\\s*)\"(.*)?\"(\\s*),(\\s*)LABEL(\\s*)=(\\s*)\"(.*)?\"(\\s*)\\]*)"

我在Pattern.compile

中使用了这种模式

现在......如果我试试这些网站：

http://www.regexr.com/

和http://ocpsoft.org/tutorials/regular-expressions/java-visual-regex-tester

使用这种模式：

(\[(\s*)\bCOD_BODY(\s*)=(\s*)"(.*)?"(\s*),(\s*)LABEL(\s*)=(\s*)"(.*)?"(\s*)\]*)

我已删除了在Java中使用的双\以逃避特殊字符

结果是：找到了7个匹配项！

但是在Java while(matcher.find())中只循环一次而不是七次！

请问，我的错在哪儿？

如果您有进一步的信息，请评论此问题。

Answer 1

我无法重现您的问题：

import java.util.regex.Matcher;
import java.util.regex.Pattern;


public class Regex {

    public Regex() {
        // TODO Auto-generated constructor stub
    }

    public static void main(String[] args) {
        String input = "Try a lot of match groups\r\n" + 
                "\r\n" + 
                "[COD_BODY=\"AZI_DIP-ANAG_AZI\", LABEL=\"Apri link1\"] come on Taranto\r\n" + 
                "\r\n" + 
                "[ COD_BODY=\"AZI_DIP-ANAG_AZI\", LABEL=\"Apri link2\"]\r\n" + 
                "\r\n" + 
                "[ COD_BODY =\"AZI_DIP-ANAG_AZI\", LABEL=\"Apri link3\"]\r\n" + 
                "\r\n" + 
                "[ COD_BODY = \"AZI_DIP-ANAG_AZI\", LABEL=\"Apri link4\"]\r\n" + 
                "\r\n" + 
                "[ COD_BODY = \"AZI_DIP-ANAG_AZI\", LABEL =\"Apri link5\"]\r\n" + 
                "\r\n" + 
                "[ COD_BODY = \"AZI_DIP-ANAG_AZI\", LABEL = \"Apri link6\"]\r\n" + 
                "\r\n" + 
                "[ COD_BODY = \"AZI_DIP-ANAG_AZI\" , LABEL = \"Apri link5\" ]";
        Pattern pattern = Pattern.compile("(\\[(\\s*)\\bCOD_BODY(\\s*)=(\\s*)\"(.*)?\"(\\s*),(\\s*)LABEL(\\s*)=(\\s*)\"(.*)?\"(\\s*)\\]*)");
        Matcher matcher = pattern.matcher(input);
        while(matcher.find()) {
            System.out.println(matcher.group());
        }
    }

}

结果：

[COD_BODY="AZI_DIP-ANAG_AZI", LABEL="Apri link1"]
[ COD_BODY="AZI_DIP-ANAG_AZI", LABEL="Apri link2"]
[ COD_BODY ="AZI_DIP-ANAG_AZI", LABEL="Apri link3"]
[ COD_BODY = "AZI_DIP-ANAG_AZI", LABEL="Apri link4"]
[ COD_BODY = "AZI_DIP-ANAG_AZI", LABEL ="Apri link5"]
[ COD_BODY = "AZI_DIP-ANAG_AZI", LABEL = "Apri link6"]
[ COD_BODY = "AZI_DIP-ANAG_AZI" , LABEL = "Apri link5" ]

Answer 2

如果您的模式与整个字符串匹配，则不应在循环中调用find()。相反，你必须从匹配器中提取组：

Matcher m = pattern.matcher(str);}
if (!m.find()) { // call find only once!
   return;
}
int n = m.groupCount();
for(int i = 1; i <= n; i++) { // starting from 1
    String capture = m.group(i); // this is the captured group.
    // deal with capture
}

带有Pattern类多组的Java RegEx

2 个答案: