我需要在scala中以下列方式构建Json格式。如何实现相同的?
{
"name": "protocols",
"children": [
{
"name": "tcp", "children": [
{
"name": "source 1",
"children": [
{
"name": "destination 1",
"children": [
{
"name": "packet 1"
},
{
"name": "packet 4"
}
]
},
{
"name": "destination 2","children": [
{
"name": "packet 1"
},
{
"name": "packet 4"
}
]
},
我需要像这样的树结构才能对文件进行修改。
答案 0 :(得分:0)
如果您正在使用游戏,您的json结构可以用单个案例类
表示这是一个示例,此案例类称为Node
import play.api.libs.json.Json
case class Node(name: String, children: List[Node] = Nil)
implicit val format = Json.format[Node]
val childSource1 = Node("destination 1", List(Node("packet 1"), Node("packet 4")))
val childSource2 = Node("destination 2", List(Node("packet 1"), Node("packet 4")))
val source1 = Node("source 1", List(childSource1, childSource2))
val example = Node("protocols", List(Node("tcp", List(source1))))
Json.prettyPrint(Json.toJson(example))