Question

我似乎无法理解如何将嵌套的JSON数组数据解析为字符串。我试图通过JSONArray解析它们，我的数据来自一个URI，所以我不能使用内联数据（而且还要知道如何使用GSON）。

我试图获得一个只有他们名字字段的艺术家名单。我只能输出艺术家数组，但它们包含每个ID和名称的所有json值。我想要的只是名字字段。我知道有一种方法可以从艺术家阵列中获取名称字段，但我无法弄清楚它的语法。

提前致谢。

这是我到目前为止所拥有的：

JSONObject resultObject = new JSONObject(result);
JSONObject responseObject = resultObject.getJSONObject("response");
JSONArray artistArray = responseObject.getJSONArray("artists : name");
String nameString1 = artistArray.getString(0);
String nameString2 = artistArray.getString(1);
String nameString3 = artistArray.getString(2);
String nameString4 = artistArray.getString(3);
String nameString5 = artistArray.getString(4);
Button output1 = (Button)getView().findViewById(R.id.button1);
Button output2 = (Button)getView().findViewById(R.id.button2);
Button output3 = (Button)getView().findViewById(R.id.button3);
Button output4 = (Button)getView().findViewById(R.id.button4);
Button output5 = (Button)getView().findViewById(R.id.button5);
output1.setText(nameString1);
output2.setText(nameString2);
output3.setText(nameString3);
output4.setText(nameString4);
output5.setText(nameString5);

来自Echo Nest URL的我的JSON数据

{"response": {"status": {"version": "4.2", "code": 0, "message": "Success"}, "artists": [{"id": "AR0PK561187B9B9EF9", "name": "TV on the Radio"}, {"id": "ARH6W4X1187B99274F", "name": "Radiohead"}, {"id": "ARAKQSI1257509D1DC", "name": "Rave Radio"}, {"id": "ARYCW5M1187B98DB6A", "name": "Radical Face"}, {"id": "ARVJWUX14801150165", "name": "Radio Doria"}]}}

Answer 1

好的，我会尝试一下。不是我开发的计算机，所以无法测试它：

起点：

{"response": {"status": {"version": "4.2", "code": 0, "message": "Success"}, "artists": [{"id": "AR0PK561187B9B9EF9", "name": "TV on the Radio"}, {"id": "ARH6W4X1187B99274F", "name": "Radiohead"}, {"id": "ARAKQSI1257509D1DC", "name": "Rave Radio"}, {"id": "ARYCW5M1187B98DB6A", "name": "Radical Face"}, {"id": "ARVJWUX14801150165", "name": "Radio Doria"}]}}

JSONObject resultObject = new JSONObject(result);
JSONObject responseObject = resultObject.getJSONObject("response");

结果：

{"status": {"version": "4.2", "code": 0, "message": "Success"}, "artists": [{"id": "AR0PK561187B9B9EF9", "name": "TV on the Radio"}, {"id": "ARH6W4X1187B99274F", "name": "Radiohead"}, {"id": "ARAKQSI1257509D1DC", "name": "Rave Radio"}, {"id": "ARYCW5M1187B98DB6A", "name": "Radical Face"}, {"id": "ARVJWUX14801150165", "name": "Radio Doria"}]}

JSONArray artistArray = responseObject.getJSONArray("artists");

应该给：

[{"id": "AR0PK561187B9B9EF9", "name": "TV on the Radio"}, {"id": "ARH6W4X1187B99274F", "name": "Radiohead"}, {"id": "ARAKQSI1257509D1DC", "name": "Rave Radio"}, {"id": "ARYCW5M1187B98DB6A", "name": "Radical Face"}, {"id": "ARVJWUX14801150165", "name": "Radio Doria"}]

你已经接近了，此时我会迭代数组，因为我认为你事先无法知道你得到了多少结果：

for (int i = 0; i < artistArray.length(); i++) {
   JSONObject artist = artistArray.getJSONObject(i);
}

对于索引0，这是：

{"id": "AR0PK561187B9B9EF9", "name": "TV on the Radio"}

现在唯一缺少的是获取名称：

for (int i = 0; i < artistArray.length(); i++) {
   JSONObject artist = artistArray.getJSONObject(i);
   String name = artist.getString("name");
   // generate button 
}

总结代码：

JSONObject resultObject = new JSONObject(result);
JSONObject responseObject = resultObject.getJSONObject("response");
JSONArray artistArray = responseObject.getJSONArray("artists");
for (int i = 0; i < artistArray.length(); i++) {
   JSONObject artist = artistArray.getJSONObject(i);
   String name = artist.getString("name");
   // generate button 
}

我认为动态生成按钮是有意义的，因为我假设你不知道你得到了多少结果。否则只需将名称存储在单独的列表中，并使用该名称列表来显示输出。

Answer 2

这就是我最终编写的内容，因为我很懒惰而且烧坏了。谢谢@cYrixmorten

                JSONObject resultObject = new JSONObject(result);
                JSONObject responseObject = resultObject.getJSONObject("response");
                JSONArray artistArray = responseObject.getJSONArray("artists");
                for (int i = 0; i < artistArray.length(); i++) {
                    JSONObject artist1 = artistArray.getJSONObject(0);
                    JSONObject artist2 = artistArray.getJSONObject(1);
                    JSONObject artist3 = artistArray.getJSONObject(2);
                    JSONObject artist4 = artistArray.getJSONObject(3);
                    JSONObject artist5 = artistArray.getJSONObject(4);
                    String name1 = artist1.getString("name");
                    String name2 = artist2.getString("name");
                    String name3 = artist3.getString("name");
                    String name4 = artist4.getString("name");
                    String name5 = artist5.getString("name");
                    Button button1 = (Button)getView().findViewById(R.id.button1);
                    Button button2 = (Button)getView().findViewById(R.id.button2);
                    Button button3 = (Button)getView().findViewById(R.id.button3);
                    Button button4 = (Button)getView().findViewById(R.id.button4);
                    Button button5 = (Button)getView().findViewById(R.id.button5);
                    button1.setText(name1);
                    button2.setText(name2);
                    button3.setText(name3);
                    button4.setText(name4);
                    button5.setText(name5);
                }

将JSON数组解析为Java中的字符串输出（Echo Nest）

这是我到目前为止所拥有的：

来自Echo Nest URL的我的JSON数据

2 个答案:

这就是我最终编写的内容，因为我很懒惰而且烧坏了。谢谢@cYrixmorten