Question

我在MySQL中有一张桌子：

+-----------------+-------------+------+-----+---------------------+-------+
| Field           | Type        | Null | Key | Default             | Extra |
+-----------------+-------------+------+-----+---------------------+-------+
| period_duration | datetime    | NO   | PRI | 0000-00-00 00:00:00 |       |
| duration        | varchar(6)  | YES  |     | NULL                |       |
| sample          | varchar(2)  | YES  |     | NULL                |       |
| corner          | varchar(10) | YES  |     | NULL                |       |
| country         | varchar(60) | NO   | PRI |                     |       |
| roaming_partner | varchar(60) | NO   | PRI |                     |       |
| pdp_in_total    | int(8)      | YES  |     | NULL                |       |
| pdp_in_ok       | int(8)      | YES  |     | NULL                |       |
| pdp_in_not_ok   | int(8)      | YES  |     | NULL                |       |
| pdp_in_ok_rate  | int(8)      | YES  |     | NULL                |       |
+-----------------+-------------+------+-----+---------------------+-------+

此表每小时都会有新的插入内容，每period_duration个roaming_partner个不同{/ 1}}：

+---------------------+----------+--------+----------+---------+-----------------------+--------------+-----------+---------------+----------------+
| period_duration     | duration | sample | corner   | country | roaming_partner       | pdp_in_total | pdp_in_ok | pdp_in_not_ok | pdp_in_ok_rate |
+---------------------+----------+--------+----------+---------+-----------------------+--------------+-----------+---------------+----------------+
| 2014-12-16 14:00:00 | 3600     | 1      | GPRS_OUT | USA     | Operator1             |          796 |       787 |             9 |             99 |
| 2014-12-16 15:00:00 | 3600     | 1      | GPRS_OUT | USA     | Operator1             |         1748 |      1706 |            42 |             98 |
| 2014-12-16 16:00:00 | 3600     | 1      | GPRS_OUT | USA     | Operator1             |            7 |         7 |             0 |            100 |

＆＃34; ok_rate＆＃34;是一个百分率。

我需要创建一个SELECT，其中会显示过去24次插入中的每个country，roaming_partner和pdp_in_ok_rate，平均值为pdp_in_ok_rate％从这些插入。

就像我希望我的SQL查询说：＆＃34;这是表格中每个运算符的最后24次插入中的平均pdp_in_ok_rate。不是在整个表格中，而是从最后的表格开始。＆＃34;

有人可以帮帮我吗？

Answer 1

这样做你想要的吗？

select country, roaming_partner, avg(pd_in_ok_rate) as avgrate
from table t
where period_duration >= date_sub(now(), interval -1 day)
group by country, roaming_partner;

这并不能为您提供平均细节。如果您还想要详细信息，可以将其用作子查询

select t.*, cr.avgrate
from table t join
     (select country, roaming_partner, avg(pd_in_ok_rate) as avgrate
      from table t
      where period_duration >= date_sub(now(), interval -1 day)
      group by country, roaming_partner
     ) cr
     on t.country = cr.country and t.roaming_partner = cr.roaming_partner
where period_duration >= date_sub(now(), interval -1 day);

MySQL - 来自上一天插入的平均值％

1 个答案: