Question

这是我的代码，在写完所有内容并测试之后链接到另一个文件。我收到这个错误。我不确定如何解决它。

解析错误：语法错误，意外＆＃39; {＆＃39;在第11行的C：\ Sanjay \ Index.php

<?php
include_once("DB.php");

//make code insert image to database
if (isset($_POST['save']))
{
    if(($_FILES['file']['type'] == 'image/gif')
    ||(($_FILES['file']['type'] == 'image/jpeg')
    ||(($_FILES['file']['type'] == 'image/pjpeg')
    && ($_FILES['file']['size'] < 2000000))
    {
        if ($_FILES['file']['error'] > 0)
        {
            echo "return code:" . $_FILES['file']['error'];
        }
        else if(file_exists('upload/'.$_FILES['file']['name']))
        {
            echo $_FILES['file']['name']."Already Exit";
        }
        else if (moved_uploaded_file($_FILES['file']['tmp_name'],
                'upload/'.$_FILES['file']['name']))
                {
                    $part = $_FILES['file']['name'];
                    $sql = mysql_query("INSERT INTO tblstudent
                                            (studentname,gender,pob,address,status,photo)
                                        VALUES('{$POST['studentname']}',
                                                '{$POST['gender']}',
                                                '{$POST['pob']}',
                                                '{$POST['address']}',
                                                '{$POST['status']}',
                                                '{$part}')");
                    if ($sql)
                    {
                        echo "successfully insert this record.....";
                    }
                }
    }
}
//end
?>

Answer 1

你错过了两个)。试试这个

if(($_FILES['file']['type'] == 'image/gif')
    ||(($_FILES['file']['type'] == 'image/jpeg')
        ||(($_FILES['file']['type'] == 'image/pjpeg')
            && ($_FILES['file']['size'] < 2000000)
        )
    )
)

Answer 2

似乎你错过了第10行的一个结束“）”。通常一个好主意，将复杂的语句（比如if中的那个）移动到单独的函数（它使代码更具可读性）。

PHP，意外{在if语句中

2 个答案: