function validateForm() {
var radios = document.getElementsByName("Dquestion[1]");
var formValid = false;
var i = 0;
while (!formValid && i < radios.length) {
if (radios[i].checked) formValid = true;
i++;
}
if (!formValid) alert("Must check some option!");
return formValid;
}
<form name="form1" action="#" onsubmit="return validateForm()" method="post">
First time visitor?:<br/>
<label for="s1">Yes</label>
<?php for($i=1; $i<=10; $i++){?><td><input type="radio" name="Dquestion[1]" value="<?=$i?>"> <?=$i?> </td><?php } ?>
<br/>
<label for="s2">No</label>
<?php for($i=1; $i<=10; $i++){?><td><input type="radio" name="Iquestion[1]" value="<?=$i?>"> <?=$i?> </td><?php } ?>
<br/>
<label for="s3">cool</label>
<?php for($i=1; $i<=10; $i++){?><td><input type="radio" name="Dquestion[2]" value="<?=$i?>"> <?=$i?> </td><?php } ?>
<br/>
<input type="submit" value="Submit"><br/>
</form>
我的意图是检查所有输入,如果没有,他们就无法提交表单。每个问题我有10个无线电输入,表格有25个问题,因此我对每个名称使用Dquestion['number']
。我正在使用此代码进行测试,但无法检查Dquestion[2]
。为什么?我如何循环所有25个问题?
我尝试了这段代码,但它没有工作:
var Dnames = ['Dquestion[1]','Dquestion[2]']
function validateForm() {
var radios = [];
var formValid = false;
for (var i = 1; i<= Dnames.length; i++){
var radios = document.getElementsByName(Dnames[i]);
var j = 0;
while(!formValid && j < radios.length){
if(radios[j].checked) formValid = true;
j++
}
}
if (!formValid) alert("Must check some option!");
return formValid;
}
答案 0 :(得分:2)
var radios = document.getElementsByName('Dquestion[1]'); // you understand this part
var checked = Array.prototype.some.call(radios, function(radio){
return radio.checked;
});
假设我有一个数组:
var arr = [1,2,3,4,5,6];
arr.some(function(num){
return boolean // meaning return something that is true or false like "return num < 3
});
//when it loops through it will return that boolean each time
// it'll return 1 < 3: true, 2 < 3: true 3 < 3: false, 4 < 3: false, 5 < 3: false, 6 < 3: false
//the some function after it's done looping is checking if some are true which is true it returned 3 trues
//so checked = true
if(checked){
console.log('one is checked');
} else {
console.log('please check one');
};
答案 1 :(得分:0)
我会在div周围包装与特定问题相关的每组单选按钮,并检查每个div以查看是否至少检查了一个单选按钮。
<form id="form1" name="form1" action="#" method="post" onsubmit="return validateForm();">
<p>First time visitor?:</p>
<div class="question">
<label for="s1">Yes</label>
<?php for($i=1; $i<=10; $i++){?><input type="radio" value="<?=$i?>"> <?=$i?> <?php } ?>
</div>
<br/>
<div class="question">
<label for="s2">No</label>
<?php for($i=1; $i<=10; $i++){?><input type="radio" value="<?=$i?>"> <?=$i?> <?php } ?>
</div>
<br/>
<div class="question">
<label for="s3">Cool</label>
<?php for($i=1; $i<=10; $i++){?><input type="radio" value="<?=$i?>"> <?=$i?> <?php } ?>
</div>
<br/>
<input type="submit" value="Submit"><br/>
</form>
function validateForm() {
var questions = document.getElementsByClassName("question"),
formValid = true;
for( var j=0; j<questions.length; j++ ) {
if( !isOneInputChecked(questions[j], "radio") ) {
formValid = false;
}
}
alert(formValid ? "Submission Succesfull!" : "Submission Failed!");
return formValid;
}
function isOneInputChecked(sel) {
// All <input> tags...
var inputs = sel.getElementsByTagName('input');
for (var k=0; k<inputs.length; k++) {
// If you have more than one radio group, also check the name attribute
// for the one you want as in && chx[i].name == 'choose'
// Return true from the function on first match of a checked item
if( inputs[k].checked )
return true;
}
// End of the loop, return false
return false;
}
这是一个有效的JSFiddle供参考。
isOneInputChecked()
函数取自Michael Berkowski的回复,用不同的帖子(link)。