Question

我有以下xml文件：

<address addr="x.x.x.x" addrtype="ipv4"/>
<hostnames>
</hostnames>
<ports><port protocol="tcp" portid="1"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="tcpmux" method="table" conf="3"/></port>
<port protocol="tcp" portid="64623"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="unknown" method="table" conf="3"/></port>
</ports>
<times srtt="621179" rttvar="35357" to="762607"/>
</host>
<host starttime="1418707433" endtime="1418707742"><status state="up" reason="syn-ack" reason_ttl="0"/>
<address addr="y.y.y.y" addrtype="ipv4"/>
<hostnames>
</hostnames>
<ports><port protocol="tcp" portid="1"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="tcpmux" method="table" conf="3"/></port>
<port protocol="tcp" portid="64680"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="unknown" method="table" conf="3"/></port>
</ports>
<times srtt="834906" rttvar="92971" to="1206790"/>
</host>
<host starttime="1418707433" endtime="1418707699"><status state="up" reason="syn-ack" reason_ttl="0"/>
<address addr="w.w.w.w" addrtype="ipv4"/>
<hostnames>
</hostnames>
<ports><extraports state="filtered" count="997">
<extrareasons reason="no-responses" count="997"/>
</extraports>
<port protocol="tcp" portid="25"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="smtp" method="table" conf="3"/></port>
<port protocol="tcp" portid="443"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="https" method="table" conf="3"/></port>
<port protocol="tcp" portid="7443"><state state="open" reason="syn-ack" reason_ttl="0"/><service name="oracleas-https" method="table" conf="3"/></port>
</ports>
<times srtt="690288" rttvar="110249" to="1131284"/>
</host>

我尝试为每个ip提取数据的是：

import sys
import xml.etree.ElementTree as ET
input=sys.argv[1]

tree=ET.parse(input)
root=tree.getroot()

for host in root.findall('host'):
    updown=host.find('status').get('state')
    if updown=='up':
        print 'IP Address: '+host.find('address').get('addr')
        ports=[port.get('portid') for port in root.findall('.//port')]
        state=[port.get('state') for port in root.findall('.//port/state')]
        name=[port.get('name') for port in root.findall('.//port/service')]

但它会返回ips的所有信息。如何获取每个IP的具体信息？

我想我应该改变root.findall，但我不知道如何做到这一点。

Answer 1

在循环内，只需将root.findall()更改为host.findall()：

for host in root.findall('host'):
    updown=host.find('status').get('state')
    if updown=='up':
        print 'IP Address: '+host.find('address').get('addr')
        ports=[port.get('portid') for port in host.findall('.//port')]
        state=[port.get('state') for port in host.findall('.//port/state')]
        name=[port.get('name') for port in host.findall('.//port/service')]

这将限制查找每个主机内的端口，状态和名称，而不是那些包含整个XML文档的端口，状态和名称。

Answer 2

对我来说，这段代码似乎很可疑：

        ports=[port.get('portid') for port in root.findall('.//port')]
        state=[port.get('state') for port in root.findall('.//port/state')]
        name=[port.get('name') for port in root.findall('.//port/service')]

在循环内部，您在整个根节点中搜索“.// port ...”的东西看来你需要这个：

        ports=[port.get('portid') for port in host.findall('.//port')]
        state=[port.get('state') for port in host.findall('.//port/state')]
        name=[port.get('name') for port in host.findall('.//port/service')]

Answer 3

指定

root.findall('.//port')

您再次从文档的根目录开始，因此返回所有端口。

ports=[port.get('portid') for port in host.findall('./ports/port')]

在python中解析xml文件的数据

3 个答案: