所以我有一张看起来像这样的表
+--------------+------------+------------+------------+
| licxp1 | licxp2 | licxp3 | licxp4 |
+--------------+------------+------------+------------+
| 2014-12-18 | 2014-10-29 | 2014-12-11 | 2014-12-01 |
| 2014-12-29 | 2014-10-22 | 2014-12-18 | 2014-12-15 |
| 2014-12-18 | 2014-11-18 | 2014-12-17 | 2014-12-12 |
| 2014-12-27 | 2014-12-19 | 2014-12-18 | 2014-12-07 |
| 2014-12-18 | 2014-12-18 | 2014-12-19 | 2014-12-05 |
| 2014-12-23 | 2014-12-18 | 2014-12-18 | 2014-12-16 |
| 2014-12-18 | 2014-12-18 | 2014-12-18 | 2014-12-18 |
+--------------+------------+------------+------------+
我从另一张桌子获取名字时需要它看起来像这样。
+---------------+--------------+
| Name | Expring lics |
+---------------+--------------+
| John Doe | 2014-10-29 |
| Johnny Cash | 2014-10-22 |
| Bruice Willis | 2014-11-18 |
| Led Zeplin | 2014-12-19 |
| Def leapord | 2014-12-18 |
| Iron Madden | 2014-12-18 |
| etc. | 2014-12-18 |
+---------------+--------------+
Expring lics字段从许可证表中获取从今天起15天内即将到期的所有到期日期。
另外我需要重复一遍，例如，如果John Doe有2个许可证我需要它显示如下：
+---------------+------------+
| John Doe | 2014-10-10 |
| John Doe | 2014-10-21 |
| John Doe | 2014-10-27 |
| John Doe | 2014-10-20 |
| John Doe | 2014-10-22 |
| Johnny Cash | 2014-10-21 |
| Bruice Willis | 2014-11-18 |
| Led Zeplin | 2014-12-19 |
| Def leapord | 2014-12-18 |
| Iron Madden | 2014-12-18 |
| etc. | 2014-12-18 |
+---------------+------------+
问我任何我对mysql都很新的事情，所以我会尽力而为
所以我有一张看起来像这样的表
+--------------+------------+------------+------------+
| licxp1 | licxp2 | licxp3 | licxp4 |
+--------------+------------+------------+------------+
| 2014-12-18 | 2014-10-29 | 2014-12-11 | 2014-12-01 |
| 2014-12-29 | 2014-10-22 | 2014-12-18 | 2014-12-15 |
| 2014-12-18 | 2014-11-18 | 2014-12-17 | 2014-12-12 |
| 2014-12-27 | 2014-12-19 | 2014-12-18 | 2014-12-07 |
| 2014-12-18 | 2014-12-18 | 2014-12-19 | 2014-12-05 |
| 2014-12-23 | 2014-12-18 | 2014-12-18 | 2014-12-16 |
| 2014-12-18 | 2014-12-18 | 2014-12-18 | 2014-12-18 |
+--------------+------------+------------+------------+
我从另一张桌子获取名字时需要它看起来像这样。
+---------------+--------------+
| Name | Expring lics |
+---------------+--------------+
| John Doe | 2014-10-29 |
| Johnny Cash | 2014-10-22 |
| Bruice Willis | 2014-11-18 |
| Led Zeplin | 2014-12-19 |
| Def leapord | 2014-12-18 |
| Iron Madden | 2014-12-18 |
| etc. | 2014-12-18 |
+---------------+--------------+
Expring lics字段从许可证表中获取从今天起15天内即将到期的所有到期日期。
另外我需要重复一遍，例如，如果John Doe有2个许可证我需要它显示如下：
+---------------+------------+
| John Doe | 2014-10-10 |
| John Doe | 2014-10-21 |
| John Doe | 2014-10-27 |
| John Doe | 2014-10-20 |
| John Doe | 2014-10-22 |
| Johnny Cash | 2014-10-21 |
| Bruice Willis | 2014-11-18 |
| Led Zeplin | 2014-12-19 |
| Def leapord | 2014-12-18 |
| Iron Madden | 2014-12-18 |
| etc. | 2014-12-18 |
+---------------+------------+
问我任何我对mysql都很新的事情，所以我会尽力而为
SELECT
id_1.full_name,
id_1.hire_date,
id_1.active,
id.professional_license,
id.license_verification,
id.cpr,
id.drivers_license,
id.car_insurance,
id.inital_competemcy_checklist,
id.annual_performance,
id.hand_washing,
id.pain_assessment,
id.competency_ev_glucometer,
id.glucometer_competency
FROM
registered_nurses id_1 INNER JOIN licenses id ON id_1.id = id.id
WHERE
id.professional_license, id.license_verification,
id.cpr,id.drivers_license,
id.car_insurance, id.inital_competemcy_checklist,
id.inital_competemcy_checklist,
id.competency_ev_glucometer,
glucometer_competency >= DATE(now())
AND
id.professional_license,
id.license_verification,
id.cpr,id.drivers_license,
id.car_insurance,
id.inital_competemcy_checklist,
id.competency_ev_glucometer,
glucometer_competency
<= DATE_ADD(DATE(now()), INTERVAL 2 WEEK)
ORDER BY
id.id
<= DATE_ADD(DATE(now()), INTERVAL 2 WEEK)
ORDER BY
id.id
答案 0 :(得分：2)
使用连接
语法：
SELECT table1.column1, table2.column2...
FROM table1
INNER JOIN table2
ON table1.common_field = table2.common_field;
SELECT users.unm,licenses.licxp1 FROM licenses INNER JOIN users ON licenses.uid = users.uid
where licenses.licxp1 <= DATE_ADD(DATE(now()), INTERVAL 5 DAY);