Question

我正在尝试从数据库表中删除一行，而我的msqli预处理语句返回false。我错误检查了$ commentId并正确地传递了它。但我找不到它不起作用的原因。

请帮助！

<?php
session_start();

include('connect.php');

if (isset($_SESSION['loggedIn']) && $_SESSION['loggedIn'] == true && $_SESSION['id'] == 43) {
    DeleteRowFunction($_POST['commentId']);
} else {
    echo "You are not authorized to delete comments";
}

function DeleteRowFunction($commentId) {
    //$deleteComment = "DELETE FROM `login`.`commenttable` WHERE `commenttable`.`id` = ?";
    $deleteComment = "DELETE FROM commenttable WHERE id = ?";
    if ($stmt = mysqli_prepare($connection, $deleteComment)) {
        mysqli_stmt_bind_param($stmt, "s", $commentId);        
        mysqli_stmt_execute($stmt);
        mysqli_stmt_close($stmt);
    } else {
        echo "error";
    }
}
?>

Answer 1

您未在功能中设置$connection变量。如果启用了错误报告，您会看到有关正在使用的未定义变量的警告。

我认为它是在connect.php中设置的，但全局变量在函数内部不可见。您必须将其作为参数传递给函数：

DeleteRowFunction($connect, $_POST['commentId']);
...
function DeleteRowFunction($connection, $commentId) {
    ...
}

或者您需要将global $connection;放在DeleteRowFunction()的开头。

MySQLi准备语句返回false

1 个答案: