Question

有三个程序可以运行不同的功能，我被告知根据用户输入的编号选项调用它们。首先，我在最后添加一个switch语句之前打开我的程序。我在switch语句中得到的错误各不相同 - 对于每种情况，我究竟需要在那些braquets中放入什么？参数？

我收到错误，包括预期的错误类。

import java.util.Scanner;
import java.lang.Math;

public class HelperMethod{
    public static boolean BookNumber(String a) {
        char f;
        int e, g, h;
        int result = 0;

        System.out.println ("Please enter a thirteen digit number");
        String a = scanner.nextLine();

        if (a.length() == 13){
            for (int i = 0; i < 13; i ++) {
                f = a.charAt(i);
                e = Character.digit(f, 10); 
                if (i % 2 == 0) {
                    g = e * 1;
                    result = result + g;
                } else {
                    g = e * 3;
                    result = result + g;
                }
            }
            System.out.println ("The added sum of you numbers is " + result);
            if (result % 10 == 0) {
                System.out.println ("This combination IS a ISBN number");
            } else {
                System.out.println ("This is NOT an ISBN number");
            } 
        } else {
            System.out.println ("This combination is not thirteen digits long");
        }
    }

    public static boolean NewtonsMethod (double guess) {
        double guess, fX, fPrimeX, newGuess;

        System.out.println ("enter in a value give"); 
        guess = userInputScanner.nextDouble();
        System.out.println ("Your guess is " + guess);
         double guess; 

        while (true) {
            fX = (6 * Math.pow (guess,4)) - (13 * Math.pow (guess,3)) - (18 * Math.pow (guess,2)) + (7 * guess) + 6;
            fPrimeX = (24 * Math.pow (guess,3)) - (39 * Math.pow (guess,2)) - 36 * guess + 7;
            newGuess = guess - (fX / fPrimeX);
            System.out.println ("A possible root is " + newGuess);
            if (Math.abs(newGuess - guess) < 0.00001) {
                break;
            } else {
                guess = newGuess;
            }
        }
        System.out.println ("The root is: " + newGuess);
    }

    public static void QuadraticFormula (double a, double b, double c) {
        Scanner keyboard = new Scanner(System.in);

        // Input 
        System.out.println("Please enter an a value:");
        double a = keyboard.nextDouble();
        System.out.println("Please enter a b value:");
        double b = keyboard.nextDouble();
        System.out.println("Please enter a c value:");
        double c = keyboard.nextDouble();

        // Calculations
        double discriminant = b * b - 4 * a * c;
        double rootOne = 0, rootTwo = 0;

        // Option A
        if (discriminant < 0) {
            System.out.println("There are no roots!");
        } else if (discriminant > 0){
            rootOne = (-b + Math.sqrt(discriminant)) / (2 * a);
            rootTwo = (-b - Math.sqrt(discriminant)) / (2 * a);
            System.out.println("Your roots are: " + rootOne + " and " + rootTwo);
        } else {
            rootOne = (-b + Math.sqrt(discriminant)) / (2 * a);
            System.out.println("Your unique root is: " + rootOne);
        }

        // Option B
        if (discriminant < 0) {
            System.out.println("There are no roots!");
        } else {
            rootOne = (-b + Math.sqrt(discriminant)) / (2 * a);
            rootTwo = (-b - Math.sqrt(discriminant)) / (2 * a);
            if (discriminant > 0) {
                System.out.println("Your roots are: " + rootOne + " and " + rootTwo);
            } else {
                System.out.println("Your unique root is: " + rootOne);
            }
        }
    }

    public static void main (String[] args) {
        Scanner userInputScanner = new Scanner (System.in);

        System.out.println ("You have three options. press one for the quadratic Formula, 2 for the newtons Method, and 3 for an ISBN checker.");
        int input = userInputScanner.nextInt();

        switch (input) {
            case 1:
                NewtonsMethod (double guess);
                break;
            case 2:
                BookNumber(String a);
                break;
            case 3: 
                QuadraticFormula (double a, double b, double c);
                break; 
        }
    }
}

Answer 1

是的，这里有很多语法错误：

NewtonsMethod(double guess);

您正在尝试调用方法，但这看起来像是一个声明。您可以在其他地方进行正确的方法调用，例如：Math.sqrt(discriminant)。所以这应该是这样的：

NewtonsMethods(guess);

然而，这些方法看起来根本不应该是参数。

public static boolean NewtonsMethod (double guess) {
    double guess, fX, fPrimeX, newGuess; 
    System.out.println ("enter in a value give"); 
    guess = userInputScanner.nextDouble();
    ...

当您调用它们时，没有任何内容可以传递给它们，并且您在方法体内收集这些变量的用户输入。这会导致您声明的方法局部变量与这些参数冲突，从而导致更多语法错误。所以，只是不要将任何参数传递给它们，你的声明看起来像：

public static boolean NewtonsMethod (double guess) {

您的退货类型也存在问题。使用布尔返回类型声明方法，但永远不返回值。在这里似乎不需要返回一个布尔值，所以我只是给它们一个void返回类型：

public static void NewtonsMethod (double guess) {

之后，我只看到其他三个语法错误。您有两个地方尝试使用尚未初始化的Scanner。您可以在QuadraticFormula和main初始化它们，因此请遵循该模式。此外，您已经在牛顿方法中将变量guess声明了两次。修复它。我相信，至少应该让你编译。我主要给你留下逻辑错误，除了这个突然出现在我身上的错误：你告诉用户按下的数字不会按你所说的去做。

在switch语句中调用类？

1 个答案: