我正在获得资源ID＃5

Question

$results=mysql_query("SELECT TIMESTAMPDIFF(SECOND,'2007-12-30 12:01:01','2007-12-31 10:02:00')");
            if(!$results)
            {
            echo mysql_error();

            }
            else
            {
                echo $resulta;
            }

当我运行此查询时，我获得资源ID＃5

Answer 1

试试这个：

$results = mysql_query("SELECT TIMESTAMPDIFF(SECOND,'2007-12-30 12:01:01','2007-12-31 10:02:00')");
    if (!$results) {
        echo mysql_error();
    } else {
        $data = mysql_fetch_assoc($results);
        var_dump($data); //check all the data that is returned
    }

旁注：您的代码容易受到sql注入攻击。不推荐使用mysql_*。建议你使用pdo

Answer 2

$results=mysql_query("SELECT TIMESTAMPDIFF(SECOND,'2007-12-30 12:01:01','2007-12-31 10:02:00')");
       while($data=mysql_fetch_row($results)){

       //your answer

     }

Answer 3

或者您也可以尝试这种方式

$results=("SELECT TIMESTAMPDIFF(SECOND,'2007-12-30 12:01:01','2007-12-31 10:02:00')");
$re = mysql_query($results) or die("wrong query".mysql_error());
 while($row= mysql_fetch_array($re))
  { 
 //your code here
  }

并且如上所述，您的代码很容易受到sql注入。