Question

我是IOS的新手，我需要你的帮助。这是我的代码。

AFJSONRPCClient *client = [AFJSONRPCClient clientWithEndpointURL:[NSURL URLWithString:url]];
[client invokeMethod:@"call" success:^(AFHTTPRequestOperation *operation, id responseObject){
        NSLog(@"response %@",responseObject);
    } failure:^(AFHTTPRequestOperation *operation, NSError *err){
        NSLog(@"errr  %@",[err description]);
    }];

我想等到答复没有到来。

Answer 1

您应该使用委托。当你得到回复时，请打电话。

Answer 2

尝试使用完成处理程序块，如下所示：

    - (void)doProcess_With_Comp:(void (^)(void))completion{
      dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{
        // Add Your process here
        AFJSONRPCClient *client = [AFJSONRPCClient clientWithEndpointURL:[NSURL URLWithString:url]];
        [client invokeMethod:@"call" success:^(AFHTTPRequestOperation *operation, id responseObject){
        NSLog(@"response %@",responseObject);
    } failure:^(AFHTTPRequestOperation *operation, NSError *err){
        NSLog(@"errr  %@",[err description]);
    }];
        dispatch_async(dispatch_get_main_queue(), ^{
          if (completion) {
            completion();
          }});
      });
    }

打电话给：

[self doProcess_With_Comp:^{
  NSLog(@"Process Completed");}];

希望它会对你有所帮助。

等到完成块未在AFJSONRPCClient请求中完成

2 个答案: