Question

我与1:n和Client之间存在Addresses关系。客户端可以有多个地址。

我创建了以下模型：

class Client extends ModelBase
{    
    $this->hasMany("id", "ClientAddress", "client_id", array(
      "alias" => "addresses"
    ));

class ClientAddress extends ModelBase
{

  public function initialize()
  {
    parent::initialize();                                              
    $this->belongsTo("client_id", "Client", "id", array(
      "alias" => "client"
    ));

    $this->belongsTo("address_id", "Address", "id", array(
      "alias" => "address"
    ));
  }

class Address extends ModelBase
{

我想在Address上执行一些CRUD操作。

我尝试创建新的Address并使用以下内容链接到ClientAddress。它确实在Address表中创建了记录，但它没有通过ClientAddress表链接到它。

$client = Client::findFirst($current_client_id);
$address = new Address();
$address->setName( $this->request->getPost("name") );
$address->setAddress1( $this->request->getPost("address1") );
$address->setAddress2( $this->request->getPost("address2") );
$address->setSuburb( $this->request->getPost("suburb") );
$address->setState( $this->request->getPost("state") );
$address->setPostcode( $this->request->getPost("postcode") );
$address->setCountry( $this->request->getPost("country") );

$client->addresses = $address;
$client->save();

我在这里做错了什么？

Answer 1

许多关系是一系列关系。一个微妙的变化，一切都应该有效。

$client->addresses[] = $address;
$client->save();

边栏：

我认为本杰明提出了关于地址关联的有效观点。想想亚马逊这样的网站，您可以从地址列表中选择要发送到的网站。它们与您的帐户相关联，而不是之前的订单。

我之前已经建立了几个电子商务和CRM关系，因此非常习惯这种模式。

Answer 2

首先，对于1：n关系，您不需要交叉表。

尝试这样的事情

class Client extends \Phalcon\Mvc\Model
{

   public function initialize()
   {
   $this->hasMany('id', 'Address', 'client_id', NULL);
   }
}


class Address extends \Phalcon\Mvc\Model{

   public function initialize()
   {
   $this->belongsTo('client_id', 'Client', 'id', array('foreignKey' => true));

   }
}

编辑：

class Client extends \Phalcon\Mvc\Model
{


    public function initialize()
    {
        $this->hasMany("id", "ClientAddress", "client_id");
    }

}


class Address extends \Phalcon\Mvc\Model
{


    public function initialize()
    {
        $this->hasMany("id", "ClientAddress", "address_id");
    }

}


class ClientAddress extends \Phalcon\Mvc\Model
{


    public function initialize()
    {
        $this->belongsTo("client_id", "Client", "id");
        $this->belongsTo("address_id", "Address", "id");
    }

}

可以通过这种方式进行通话

$client = Client::findFirst($current_client_id);
$address = new Address();
...
$address->save();
$clientAddress  = new ClientAddress ();

$clientAddress->setClient_id($client->getId());
$clientAddress->setAddress_id($cddress_id->getId());
$clientAddress->save();

当出现问题时，可能会添加一些检查和回滚。

向Phalcon模型添加新记录未正确创建关系

2 个答案: