Question

我无法理解如何将上传的文件内容发送到我的ASPX服务器端。这适用于HTML-4实现，其中File API在客户端不可用，并且使用.NET v4.0。

这是我到目前为止所拥有的：

FileReceiver.aspx上的HTML：

<input type="button" id="uploadFile" value="Upload" /> 
<div class="hidden">
    <form id="uploadFileForm">
        <input type="file" id="browseForFiles" />
    </form>
</div>

（客户端）JS：

$("#uploadFile").click(function () {
    $("#browseForFiles").click();
});

$("#browseForFiles").change(function () {
    $("#uploadFileForm").submit();
});

$("#uploadFileForm").submit(function (e) {

    // prevent default action
    e.preventDefault();

    // send file to server
    $.ajax({
        url: "FileReceiver.aspx/ReceiveFile",
        type: "post",
        dataType: "multipart/form-data", // <---- is this right?
        data: ???, // <-------------------------- what goes here? 
        success: function(data) { 
            // do something on success 
        } 
    }); 
});

（服务器端）FileReceiver.aspx.cs：

[WebMethod]
public static string ReceiveFile(??? receivedFile) // <-- what type goes here?
{
    // do something and return status
}

请帮助填写两个＆＃34; ???＆＃34;在上面的代码中。提前谢谢！

Answer 1

这应该有效

$("#uploadFileForm").submit(function (e) {

    // prevent default action
    e.preventDefault();

    var formData = new FormData($('#uploadFileForm')[0]);
    $.ajax({
        url: "FileReceiver.aspx/ReceiveFile",
        type: "POST",
        // Form data
        data: formData, // <-- see above to see where this comes from
        dataType: "json", // <-- the dataType you're RETURNING, not sending
        cache: false,
        //Options to tell jQuery not to process data or worry about content-type.
        contentType: false,
        processData: false,
        success: function(data) { 
            // do something on success 
        } 
    });
});

然后你的C＃代码应该是这样的

[WebMethod]
public static string ReceiveFile(HttpPostedFileBase receivedFile) 
{
    // do something and return status
}

将文件上载到ASPX服务器端页面

1 个答案: