Question

我正在使用Scala和Akka开始一个新项目，并且在编写测试时遇到了麻烦。在我的测试中，我使用List检查两个should equal对象的相等性：

actualBook should equal (expectedBook)

我的测试套件中的所有内容都会编译并运行，但测试失败并显示以下消息：

org.scalatest.exceptions.TestFailedException: List(BookRow(A,100.0,10.6)) did not equal List(BookRow(A,100.0,10.6))

显然，测试正在通过（即，两个List个对象包含相同的内容）。不确定这是否相关，但actualBook和expectedBook具有相同的哈希码（actualBook(0)和expectedBook(0)也具有相同的哈希码。）

我想知道问题是否是由于......

我使用了错误的比较运算符
我没有明确定义比较BookRow对象的方法。

这里参考我的测试代码：

包高峰

import cucumber.api.DataTable
import org.scalatest.Matchers._
import scala.collection.JavaConversions._
import cucumber.api.java.en.{When, Then}

class OrderBookSteps {

  val orderTypes = OrderType.all()

  val buyBook: OrderBook = new OrderBook(Bid, orderTypes)

  val sellBook: OrderBook = new OrderBook(Ask, orderTypes)

  @When("""^the following orders are added to the "(.*?)" book:$""")
  def ordersAddedToBook(sideString: String, orderTable: DataTable) {

    val (side, book) = getBook(sideString)

    val orders = orderTable.asList[OrderRow](classOf[OrderRow]).toList.map(
  r => LimitOrder(r.broker, side, r.volume, r.price.toDouble))
    orders.foreach(book.add)
  }

  @Then("""^the "(.*?)" order book looks like:$""")
  def orderBookLooksLike(sideString: String, bookTable: DataTable) {

    val (_, book) = getBook(sideString)
    val expectedBook = bookTable.asList[BookRow](classOf[BookRow]).toList
    val actualBook = book.orders().map(o => BookRow(o.broker, o.volume, orderTypes(o).bookDisplay))

    actualBook should equal (expectedBook)
  }

  def getBook(side: String) = side match {
    case "Bid" => (Bid, buyBook)
    case "Ask" => (Ask, sellBook)
  }

  case class OrderRow(broker: String, volume: Double, price: String)

  case class BookRow(broker: String, volume: Double, price: String)

}

Answer 1

您可以尝试：

List(BookRow(A,100.0,10.6)).toSeq should equal (List(BookRow(A,100.0,10.6)).toSeq)

或者：

List(BookRow(A,100.0,10.6) should contain theSameElementsAs List(BookRow(A,100.0,10.6))

假设你有BookRow（普通类）等于被覆盖。

Answer 2

我找到了解决方案，虽然我不明白为什么会这样！我只需要替换：

case class OrderRow(broker: String, volume: Double, price: String)

case class BookRow(broker: String, volume: Double, price: String)

与

private case class OrderRow(broker: String, volume: Double, price: String)

private case class BookRow(broker: String, volume: Double, price: String)

我想知道为什么会这样。

将列表与scalatest进行比较

2 个答案: