CakePHP HABTM条件

Question

我想对我的HABTM属性做出规定 我在CakePHP 2.x中有以下HABTM关系：

Practise.php

public $hasAndBelongsToMany = array(
    'Attribute' => array(
        'className' => 'Attribute',
        'joinTable' => 'practises_attributes',
        'foreignKey' => 'practise_id',
        'associationForeignKey' => 'attribute_id',
        'unique' => true,
        'conditions' => '',
        'fields' => '',
        'order' => '',
        'limit' => '',
        'offset' => '',
        'finderQuery' => '',
    )
);

Attribute.php

public $hasAndBelongsToMany = array(
    'Practise' => array(
        'className' => 'Practise',
        'joinTable' => 'practises_attributes',
        'foreignKey' => 'attribute_id',
        'associationForeignKey' => 'practise_id',
        'unique' => true,
        'conditions' => '',
        'fields' => '',
        'order' => '',
        'limit' => '',
        'offset' => '',
        'finderQuery' => '',
    )
);

现在我想在我的PractiseController.php

中找到所有包含属性的条件

PractiseController.php

$cond['Attribute.id'] = array(1,2,3);
$this->Practise->find('all', array('conditions' => $cond));

然后我收到以下错误：

错误：SQLSTATE [42S22]：找不到列：1054'where子句'中的未知列'Attribute.id'

SQL查询：

选择         Practise。id，         Practise。title，         Practise。body，     来自db。practises AS Practise     在Attribute。id IN（1,2,3）

如何使CakePHP也将HABTM表加入查找查询？

Answer 1

您可以使用包含例如

$this->Practise->find('all', array('contain' => 'Attribute.id = whatever'));

您也可以手动加入：

$options['joins'] = array(
    array('table' => 'practises_attributes',
        'alias' => 'PractiseAttribute',
        'type' => 'INNER',
        'conditions' => array(
            'Attribute.id = whatever',
        )
    ) );