Question

我正在运行一个基本的刽子手游戏，代码可以工作，但我目前陷入了一个涉及如何计算得分的逻辑错误，该程序允许用户多次输入相同的单词并仍然给予胜利

例如：如果从我的列表中随机挑选的单词是＆＃34; apple＆＃34;并且用户输入＆＃34; p＆＃34;如果他们输入＆＃34; p＆＃34;他们再也不会透露任何更多的信件，但他们仍然会在胜利中获得两分，如果他们输入了＃34; p＆＃34;再一次，用户将赢得比赛

这是代码：

#include <iostream>
#include <cstdlib>
#include <ctime>
#include <string>
#include <fstream>
#include <vector>

using namespace std;

int main()
{
    const int maxWrongGuesses = 10;
    int letter;
    char guess;
    string display;
    bool won = false;
    bool guessing = true;
    int correctGuesses = 0;
    int wrongGuesses = 0;

    cout << "Lets Play a Game of Hangman!!! \n";

    vector<string> word;
    string line;
    ifstream hangmanfile("hangman.txt");
    if (hangmanfile.is_open())
    {
        while (getline(hangmanfile, line))
        {

            word.push_back(line);
        }
        hangmanfile.close();
    }
    else cout << "Unable to open file";

    unsigned seed = time(0);

    srand(seed);
    int answer = rand() % word.size();

    string currentWord = word.at(answer);

    cout << currentWord << "\n";
    for (int i = 0; i < currentWord.length(); i++)
    {
        display = display + "_ ";
    }
    while (guessing)
    {
        bool correctGuess = false;
        cout << display << "\n";

        cout << "Please Enter Your Guess \n";
        cin >> guess;

        for (int i = 0; i < currentWord.length(); i++)
        {
            if (guess == currentWord[i])
            {
                display[i * 2] = guess;
                correctGuesses++;
                correctGuess = true;
            }
            if (correctGuesses == currentWord.length())
            {
                guessing = false;
                won = true;
            }
        }
        if (!correctGuess)
        {
            cout << "Wrong Try Again \n";
            wrongGuesses++;
            cout << wrongGuesses << "\n";
        }
        if (maxWrongGuesses == wrongGuesses)
        {
            guessing = false;
        }

    }
    if (won)
    {
        cout << display << "\n";
        cout << "Congratz You Won!! \n";
    }
    else
    {
        cout << "The Answer Was " << currentWord << "\n";
        cout << "Sorry You Lose \n";
    }
    return 0;
}

如何解决这个问题背后的逻辑让我难以忍受睡眠和长时间的工作，我想但我需要一些帮助来解决这个问题。

Answer 1

只有在display[index]=='_'且用户正确填写了字母时才会添加积分。我想你可以从这里拿走它。

在计算我的刽子手游戏的分数背后的逻辑有问题

1 个答案: