Question

我遇到了Java分配问题。我需要构建一个程序，允许某人从彩票中输入6个数字。然后，用户将从其票证中输入另外6个号码。然后程序将检查该抽奖的匹配数量。任何少于3场比赛的门票都不是赢家。我需要提供一条消息，说明是否有3,4,5或6个匹配项。我在课程笔记中找不到任何相关内容。下面是我到目前为止编写的代码：

import java.util.Scanner;
//Activates scanner utility

public class lottery 
{
    public static void main(String[]args)
    {
        Scanner in = new Scanner(System.in);
        //Names scanner, completes activating scanner

        int array1[] = new int [6];
        System.out.print("Enter Winning Numbers:");
        for(int j=0;j<array1.length;j=j+1){
            array1[j] = in.nextInt();   
        }

        System.out.print("Winning Numbers Are: ");
        for(int j=0;j<array1.length;j=j+1){
            System.out.print(array1[j]+" ");
        }

        int yourNumbers[] = new int [6];
        System.out.println();
        System.out.print("Enter Your Numbers:");
        for(int j=0;j<yourNumbers.length;j=j+1){
            yourNumbers[j] = in.nextInt();
        }

        System.out.println("Your Numbers Are: ");
        for(int j=0;j<yourNumbers.length;j=j+1){
            System.out.print(yourNumbers[j]+" ");
        }

        System.out.println();
        if(array1==yourNumbers){
            System.out.println("6 Numbers Match - JACKPOT WINNER!!!");;
        } else {
            System.out.print("Not a Winner - Better Luck Next Time.");
        }

        in.close();
        //Deactivates the scanner utility
    }
}

Answer 1

如果定位不重要，

f1zz0_13＆＃39的回答是有效的。
如果数字必须相同且位于相同位置，则执行以下操作：

//your code:
System.out.println("Your Numbers Are: ");
for(int j=0;j<yourNumbers.length;j=j+1){
   System.out.print(yourNumbers[j]+" ");
}

//new stuff:
System.out.println();
int similar = 0;
for(int i = 0; i < array1.length; i++) {
    if(array1[i] == yourNumbers[i]) {
        similar++;
    }
}

if (similar >= 3) {
    System.out.println(similar + " Numbers Match - JACKPOT WINNER!!!");
}
else {
    System.out.print("Not a Winner - Better Luck Next Time.");
}
//close the scanner then end the function...

Answer 2

int count = 0;
for (int i = 0; i < 6; i++)
    for (int j = 0; j < 6; j++)
      if (array1[i] == yourNumbers[j]) {
          count++;
          break;
      }

假设6个彩票号码是唯一的，在您输入输入后添加这段代码应该会给出与变量count中的彩票号码匹配的数量。

比较两个数组中的数据值

2 个答案: