Question

我可能以错误的方式使用枚举，但这是我的前提。我基本上有一组3个字符串，可以按任何顺序排列。而我想要做的就是选择符合此顺序的枚举。基本上我想知道哪些场景适用于进来的字符串。

我一直在研究测试应用程序，只是为了选择正确的Possibility。也许下面的代码会更有意义。下面的foreach循环也可能不是最好的方法。在下面的代码中，您可以看到我{ "Cow", "Chicken", "Egg" };我希望将其与枚举Scenario2

相匹配

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace EnumEnumerables
{
class Program
{

    enum Possibilitys
    {
        Scenario1 = Options.Chicken + Options.Cow + Options.Egg,
        Scenario2 = Options.Cow + Options.Chicken + Options.Egg,
        Scenario3 = Options.Egg + Options.Cow + Options.Chicken
    }

    enum Options
    {
        Chicken,
        Cow,
        Egg

    }
    static void Main(string[] args)
    {
        //this should result in scenario 1
        //string[] myOrderofHistory = { "Chicken", "Cow", "Egg" };

        //this should result in scenario 2
        string[] myOrderofHistory = { "Cow", "Chicken", "Egg" };

        foreach (string history in myOrderofHistory)
        {
            foreach (var value in Enum.GetValues(typeof(Possibilitys)))
            {
                if (value == history)
                {
                    Console.WriteLine("{0,3}     0x{0:X8}     {1}",
                       (int)value, ((Possibilitys)value));
                }

            }
        }
    }
}

}

Answer 1

我绝不会建议使用这样的枚举，而是通过创建[Flags] Enum并使用左移位运算符＆lt;＆lt;你可以这样做：

class Program
{
    [Flags]
    enum Options
    {
        None = 0,
        Chicken = 1,
        Cow = 2,
        Egg = 4,
    }

    enum Possibilities
    {
        Order1 = (Options.Chicken << 4) + (Options.Cow << 2) + Options.Egg,
        Order2 = (Options.Cow << 4) + (Options.Chicken << 2) + Options.Egg,
        Order3 = (Options.Egg << 4) + (Options.Cow << 2) + Options.Chicken,
    }

    static void Main(string[] args)
    {
        //this should result in scenario 1
        //string[] myOrderofHistory = { "Chicken", "Cow", "Egg" };

        //this should result in scenario 2
        string[] myOrderofHistory = { "Cow", "Chicken", "Egg" };
        int[] shiftValue = new int[] { 4, 2, 0 };

        int shiftIndex = 0;
        int possibility = 0;
        foreach (string history in myOrderofHistory)
        {
            Options options = (Options)Enum.Parse(typeof(Options), history);

            possibility += ((int)options) << shiftValue[shiftIndex];

            shiftIndex++;
        }

        Console.WriteLine(((Possibilities)possibility).ToString());

        Console.WriteLine("Press any key...");
        Console.ReadKey();
    }
}

如何枚举值并确定哪个是枚举的正确方案

1 个答案: