Question

我正在尝试创建一个刽子手游戏。

我收到此错误消息：

Traceback (most recent call last):
File "C:/Users/<user>/Downloads/wordgame.py", line 23, in <module>
so_far= "-" * len(word)
NameError: name 'word' is not defined

如果有人可以帮我解决如何解决这个问题，如果可以，请查看我的代码并给我一些提示，如果我朝着正确的方向前进，无论如何要改进。谢谢。

import random
HANGMAN = ('''
 O''', '''

 O    
 |''', '''

 O    
/|\ ''', '''

 O    
/|\ 
  \ ''', '''

 O    
/|\ 
/ \ ''')

words=['train','tees','tweed','conquer','conquet','washing']
lives = len(HANGMAN) - 1
wrong = 0
used = []
so_far= "-" * len(word)

print ("Welcome to Hangman!")

def pickaword():
    word = random.choice(words)
    return word

def displayBoard(HANGMAN, wrongLetters, correctLetters, word):
    print (HANGMAN[len(missedLetters)])
    print ("wrong letters:")
    for letter in wrongLetters:
        print (letter, end )

def guessaletter(guessedLetters):
    while True:
        guess = raw_input("Guess a letter.")
        guess = guess.lower()
        if len(guess) != 1:
            print("Please only enter a single letter.")
        # Stops user from inputing more that 1 letter.
        elif guess in guessedLetters:
            print("You have already guessed that letter. Choose again!")
        # Stops user from guessing the same letter twice.
        elif guess not in "abcdefghijklmnopqrstuvwyz":
            print("Please enter a valid letter")
        # Stops user from enterting a invalid letter
        else:
            return guess

def guessaword(word, wrong, so_farm, lives):
    while wrong < lives and so_far != word:
        print (HANGMAN[wrong])
        print ("You have used the following letters:" + used)
        print ("So farm the word is", + so_far)



"""def reveal(hidden, guessedLetters):
    display = ''
    for letter in hidden:
        letter += display        
    else:
        lives -=1

    return display"""

Answer 1

您也可以使用全局

def pickaword():
    global word
    word = random.choice(words)

然后使用函数外的全局变量或者使用另一个函数。

Answer 2

这是因为你试图得到一个不存在的变量word的长度。

您需要先使用pickaword功能，才能为word提供值：

word = pickaword()

一个好的下一步，也可以帮助理解这个问题，就是开始制作用户玩游戏的功能或循环。您需要做的第一件事就是为用户选择一个词来猜测。只有在您选择了一个单词后，才能显示so_far。但如果没有选择一个单词，那么你需要多少破折号就不清楚了。

你在guessaword中也有一个拼写错误：第三个参数可能是so_far。

NameError：name＆＃39; word＆＃39;在刽子手游戏中没有定义

2 个答案: