Question

我正在做一个基于菜单的程序，我想要它，所以当你打开脚本它会说。＆＃34;正在加载菜单等待..＆＃34; 然后菜单将开始出现，但不是马上它会一次开始出现一个单词，好像我在那里写出来然后如果你找到我。到目前为止我有这样的例子：

    #Imports time so i can delay things:D
import time

# This will ask the end user to input his/her choice ;D
def area():
    print("Loading Menu please wait..")
    time.sleep(2)
    print ("  _______________")
    time.sleep(1)
    print ("||               ||")
    time.sleep(1)
    print ("||Area Calculator||")
    time.sleep(1)
    print ("||     V1.0      ||")
    time.sleep(1)
    print ("||  By William F ||")
    time.sleep(1)
    print ("||_______________||")
    time.sleep(1)
    print ("Please Select A Shape")
    time.sleep(1)
    print ("1. Square")
    time.sleep(1)
    print ("2. Rectangle")
    time.sleep(1)
    print ("3. Circle")
    time.sleep(1)
    print ("4. Triangle")
    time.sleep(1)
    print ("5. Exit")
    print()
    time.sleep(1)
    return

#This will call the function to display the menu
area()

这有效，但我希望它在加载时输入自己，所以我尝试添加这个：

print ("  _", time.sleep(1),"______________")

要在每个字母之后添加，但是当我在一个字母上进行测试时，它会显示＆＃34;无＆＃34;睡觉的时间在哪里？有任何想法吗？非常感谢。非常感谢。

Answer 1

这是一个可以帮助你的功能：

import time
import sys


def slowshow(text, delay=0.2):
    for c in text:
        time.sleep(delay)
        sys.stdout.write(c)
    print ""

slowshow("Hello, I am Reut Sharabani!")

更有趣的一个版本是让它同步，这样你就可以在不阻止程序的情况下进行计算：

import time
import sys
import threading

# lock the sys.stdout stream when a thread is printing.
slowshow_lock = threading.Lock()

def slowshow(text, delay=0.2):
    slowshow_lock.acquire()
    for c in text:
        time.sleep(delay)
        sys.stdout.write(c)
    print ""
    slowshow_lock.release()

# they will show when needed
threading.Thread(target=slowshow, args=("Hello, I am Reut Sharabani!", )).start()
threading.Thread(target=slowshow, args=("Hello, I am Albus Dumbledore!",)).start()

# this should show immediately, even though we've sent text to printing!
print "VERY COMPLEX BACKGROUND CALCULATION"

Answer 2

用它来做它＆＃34;键入自己＆＃34 ;;这只是删除换行符：

import sys, time
sys.stdout.write(' _')
time.sleep(1)
sys.stdout.write('____________")

输出：

 _(1 second wait)_____________

如何编写类型python脚本的代码

2 个答案: