Question

这是我想要取消的Xml文件：

<?xml version="1.0"?>
<AddressDirectory>
  <Address>
    <HouseNo>1</HouseNo>
    <StreetName>Pitampura</StreetName>
    <City>Delhi</City>
  </Address>
  <Address>
    <HouseNo>4</HouseNo>
    <StreetName>Rohini</StreetName>
    <City>Delhi</City>
  </Address>
</AddressDirectory>

这些是我的课程：

public class AddressDirectory
{
    [XmlElement("Address")] 
    public List<Address> addressList = new List<Address>(); 
}
public class Address
{
    public int HouseNo { get; set; }
    public string StreetName { get; set; }
    public string City { get; set; }
}

这是我的主要内容：

XmlSerializer deserializer = new XmlSerializer(typeof(AddressDirectory));
TextReader reader = new StreamReader(@"D:\myXml.xml");
object obj = deserializer.Deserialize(reader);
AddressDirectory XmlData = (AddressDirectory)obj;
reader.Close();

这就是我访问必须保存在列表中的元素的方式：

XmlData.addressList[0].HouseNo;
XmlData.addressList[0].StreetName; 
XmlData.addressList[0].City;

或在循环中，我这样访问：

for (int i = 1; i < 10; i++)
            {
                Console.Write("house number for {0}: ", i);
                Console.WriteLine(XmlData.addressList[i].HouseNo);
                Console.Write("Street Name  for {0}: ", i);
                Console.WriteLine(XmlData.addressList[i].StreetName);
                Console.Write("City         for {0}: ", i);
                Console.WriteLine(XmlData.addressList[i].City);
            }

这是我执行程序时遇到的错误：

指数超出范围。必须是非负数且小于集合。

我想这是因为我们没有在列表中添加任何内容。因为要添加到列表中，我们必须在main中的某处使用List.Add（）。

这是编辑后的主要（）：

XmlSerializer deserializer = new XmlSerializer(typeof(AddressDirectory));
            TextReader reader = new StreamReader(@"D:\addressDirectory.xml");
            object obj = deserializer.Deserialize(reader);
            AddressDirectory XmlData = (AddressDirectory)obj;
            reader.Close();


            for (int i = 0; i < XmlData.addressList.Count; i++)
            {
                Console.WriteLine("Information for item #{0}", i + 1);
                Console.WriteLine(" - House Number ... {0}", XmlData.addressList[i].HouseNo);
                Console.WriteLine(" - Street Name .... {0}", XmlData.addressList[i].StreetName);
                Console.WriteLine(" - City ........... {0}", XmlData.addressList[i].City);
            }
            Console.ReadLine();

现在它不会出现任何错误，也不会显示列表的内容

Answer 1

尝试将XmlData.addressList.Count属性用于for条件：

for (int i = 0; i < XmlData.addressList.Count; i++)
{
    Console.WriteLine("Information for item #{0}", i + 1);
    Console.WriteLine(" - House Number ... {0}", XmlData.addressList[i].HouseNo);
    Console.WriteLine(" - Street Name .... {0}", XmlData.addressList[i].StreetName);
    Console.WriteLine(" - City ........... {0}\n", XmlData.addressList[i].City);
}

以下是另一种方法，以及我用来测试它的其余代码（适用于您的xml文件和类）：

public static void Main()
{        
    var addresses = new List<Address>();
    var deserializer = new XmlSerializer(typeof(AddressDirectory));
    using (var reader = new StreamReader(@"C:\Users\Rufus\Documents\temp\temp.xml"))
    {
        addresses.AddRange(
            ((AddressDirectory)deserializer.Deserialize(reader)).addressList);
    }

    int counter = 1;
    foreach (var address in addresses)
    {
        Console.WriteLine("Information for item #{0}", counter++);
        Console.WriteLine(" - House Number ... {0}", address.HouseNo);
        Console.WriteLine(" - Street Name .... {0}", address.StreetName);
        Console.WriteLine(" - City ........... {0}\n", address.City);
    }
}

从列表C＃访问存储反序列化XML的数据

1 个答案: