Question

编辑： *有人可以帮我理解时间变量的行为方式吗？外出来的样子如下：

c:\directory><
for /D /r %%F IN ("*") DO ( 
   for %%G  IN ("%%F\*.sdf") DO xcopy "%%G" c:\Path2\%newest% /y /i 
for /f "delims=_" %%J IN ('forfiles /p "%%F" /m *.extension /c "cmd /c echo @path"')  DO start "Program"  /D "c:\program files\Path2" /Wait jmpt -r  %%J
set ENDTIME=(whatever the current time is)
echo STARTTIME:
echo ENDTIME:
set /a DURATION=-
endlocal
rem this ends the runtime segment
>

所以我有一个批处理文件，它将使用for循环执行多个文件。我试图添加一个脚本来测量每个文件执行所需的时间（而不是整个批处理文件）。或者换句话说，我想测量循环的每次迭代完成所需的时间。同事给了我一个批处理工作时间，但是当我尝试将其实现到我的批处理文件中时，它会在运行的最开始设置开始和结束时间，并且永远不会更新它。

这是他的批处理文件

@ECHO OFF
set PATH=%PATH%;C:\Path

set STARTTIME=%TIME%

rem here begins the command you want to measure
@ECHO %PATH%
rem here ends the command you want to measure
rem (I, the stackoverflow asker, just used @ECHO %PATH% to test if his script worked)

set ENDTIME=%TIME%

rem output as time
echo STARTTIME: %STARTTIME%
echo ENDTIME: %ENDTIME%

rem convert STARTTIME and ENDTIME to centiseconds
set /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 + (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)
set /A ENDTIME=(1%ENDTIME:~0,2%-100)*360000 + (1%ENDTIME:~3,2%-100)*6000 + (1%ENDTIME:~6,2%-100)*100 + (1%ENDTIME:~9,2%-100)

rem calculating the duratyion is easy
set /A DURATION=%ENDTIME%-%STARTTIME%

rem we might have measured the time in between days
if %ENDTIME% LSS %STARTTIME% set /A DURATION=%STARTTIME%-%ENDTIME%

rem now break the centiseconds down to hours, minutes, seconds and the remaining centiseconds
set /A DURATIONH=%DURATION% / 360000
set /A DURATIONM=(%DURATION% - %DURATIONH%*360000) / 6000
set /A DURATIONS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000) / 100
set /A DURATIONHS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000 - %DURATIONS%*100)

rem some formatting
if %DURATIONH% LSS 10 set DURATIONH=0%DURATIONH%
if %DURATIONM% LSS 10 set DURATIONM=0%DURATIONM%
if %DURATIONS% LSS 10 set DURATIONS=0%DURATIONS%
if %DURATIONHS% LSS 10 set DURATIONHS=0%DURATIONHS%

rem outputing
echo STARTTIME: %STARTTIME% centiseconds
echo ENDTIME: %ENDTIME% centiseconds
echo DURATION: %DURATION% in centiseconds
echo %DURATIONH%:%DURATIONM%:%DURATIONS%,%DURATIONHS%

endlocal

现在我的批处理文件看起来像这样（带有他的实现）

RMDIR c:\directory /s /q
mkdir c:\directory
xcopy "\\Path1\*" c:\directory /s /i
cd c:\Path2
for /f "tokens=*" %%a in ('dir /b /od') do set newest=%%a
cd c:\directory
sqlcmd -S Server -i "\\Path3\query1.sql"

for /D /r %%F IN ("*") DO ( 
   for %%G  IN ("%%F\*.sdf") DO xcopy "%%G" c:\Path2\%newest% /y /i 

@ECHO OFF

set STARTTIME=%TIME%

   for /f "delims=_" %%J IN ('forfiles /p "%%F" /m *.extension /c "cmd /c echo @path"')  DO start "Program"  /D "c:\program files\Path2" /Wait jmpt -r  %%J




set ENDTIME=%TIME%

rem output as time
echo STARTTIME: %STARTTIME%
echo ENDTIME: %ENDTIME%

rem convert STARTTIME and ENDTIME to centiseconds
set /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)
set /A ENDTIME=(1%ENDTIME:~0,2%-100)*360000 + (1%ENDTIME:~3,2%-100)*6000 + (1%ENDTIME:~6,2%-100)*100 + (1%ENDTIME:~9,2%-100)

rem calculating the duratyion is easy
set /A DURATION=%ENDTIME%-%STARTTIME%

rem we might have measured the time inbetween days
if %ENDTIME% LSS %STARTTIME% set set /A DURATION=%STARTTIME%-%ENDTIME%

rem now break the centiseconds down to hors, minutes, seconds and the remaining centiseconds
set /A DURATIONH=%DURATION% / 360000
set /A DURATIONM=(%DURATION% - %DURATIONH%*360000) / 6000
set /A DURATIONS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000) / 100
set /A DURATIONHS=(%DURATION% - %DURATIONH%*360000 - %DURATIONM%*6000 - %DURATIONS%*100)

rem some formatting
if %DURATIONH% LSS 10 set DURATIONH=0%DURATIONH%
if %DURATIONM% LSS 10 set DURATIONM=0%DURATIONM%
if %DURATIONS% LSS 10 set DURATIONS=0%DURATIONS%
if %DURATIONHS% LSS 10 set DURATIONHS=0%DURATIONHS%

rem outputing
echo STARTTIME: %STARTTIME% centiseconds
echo ENDTIME: %ENDTIME% centiseconds
echo DURATION: %DURATION% in centiseconds
echo %DURATIONH%:%DURATIONM%:%DURATIONS%,%DURATIONHS%


endlocal
)

sqlcmd -S Server -i "\\path3\query2.sql"

pause

当我使用这些添加项运行我的批处理文件时，我得到一个开始和结束时间（在文件实际开始运行之前设置）彼此相等，它们将等于上一个开始和结束时间迭代和即将到来的迭代。

任何想法是什么交易？

Answer 1

在您的代码中，

set /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)

在+

之后，你错过了*6000

set /A STARTTIME=(1%STARTTIME:~0,2%-100)*360000 + (1%STARTTIME:~3,2%-100)*6000 + (1%STARTTIME:~6,2%-100)*100 + (1%STARTTIME:~9,2%-100)

在原始代码中：

if %ENDTIME% LSS %STARTTIME% set set /A DURATION=%STARTTIME%-%ENDTIME%

set重复 - 显然，该代码从未在午夜进行过测试。

在两者中，如果endime小于starttime，正确的计算是将3600 * 2400（3600秒/小时* 24小时/天* 100厘秒）添加到结果（负）持续时间。

Answer 2

如何使用合适的工具来完成工作。

Using WPT For Batch Script Profiling

这应该可以让您对批处理skripts有足够的深入了解，如果您想了解执行命令的原因，可以打开执行命令的其他分析。

如何测量批处理文件中循环的执行时间

2 个答案: