运行上载文件代码时HTTP状态404错误

时间:2014-12-12 18:31:03

标签: java jsp upload

我在单击“提交”按钮时收到错误“HTTP状态404 - 未找到”。给出的路径似乎是正确的。这段代码有什么可能导致错误的发生吗?

<form name="uploadForm" action="index.jsp" method="POST" enctype="multipart/form-data">
        <%
            String saveFile="";
            String contentType = request.getContentType();

            if((contentType != null)&&(contentType.indexOf("multipart/form-data") >= 0)){

                DataInputStream in = new DataInputStream(request.getInputStream());
                int formDataLength = request.getContentLength();
                byte dataBytes[] = new byte[formDataLength];
                int byteRead = 0;
                int totalBytesRead = 0;

                while(totalBytesRead < formDataLength){
                    byteRead = in.read(dataBytes, totalBytesRead,formDataLength);
                    totalBytesRead += byteRead;
                }

                String file = new String(dataBytes);
                saveFile = file.substring(file.indexOf("filename=\"") + 10);
                saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
                saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
                int lastIndex = contentType.lastIndexOf("=");
                String boundary = contentType.substring(lastIndex + 1,contentType.length());
                int pos;
                pos = file.indexOf("filename=\"");
                pos = file.indexOf("\n", pos) + 1;
                pos = file.indexOf("\n", pos) + 1;
                pos = file.indexOf("\n", pos) + 1;
                int boundaryLocation = file.indexOf(boundary, pos) - 4;
                int startPos = ((file.substring(0, pos)).getBytes()).length;
                int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;

                File ff = new File("C:/Users/JBG/Desktop/SampleFile2.docx"+saveFile);

                try{
                    FileOutputStream fileOut = new FileOutputStream(ff);
                    fileOut.write(dataBytes, startPos, (endPos - startPos));
                    fileOut.flush();
                    fileOut.close();}catch(Exception e){out.println(e);}
            }
        %>

        <input type="file" name="file" value="" />
        <input type="submit" value="Submit" name="submit" />
    </form>

2 个答案:

答案 0 :(得分:2)

当您收到404错误消息时。此错误消息表明

The 404 or Not Found error message is a HTTP standard response code indicating that the client was able to communicate with a given server, but the server could not find what was requested.

The web site hosting server will typically generate a "404 Not Found" web page when a user attempts to follow a broken or dead link; hence the 404 error is one of the most recognizable errors users can find on the web.[1]

因此,文件操作在行下方正确时会出现一点错误。

代码

File ff = new File("C:/Users/JBG/Desktop/SampleFile2.docx"+saveFile);

替换以下语法。

File ff = new File("C:/Users/JBG/Desktop/directory_name/"+saveFile);

OR

File ff = new File("C:/Users/JBG/Desktop/"+saveFile);

答案 1 :(得分:0)

您的操作标记应指向有效的端点servlet / webservice。看起来你将它指向一个jsp文件。也就是说,混合表示逻辑和服务器端逻辑是在21世纪初完成的。在过去十年中,情况有了很大改善。我的建议是看看Jersey + Twitter Bootstrap甚至Play来实现你正在做的事情。