是否可以仅向第一个菜单项(menu-itemfirst)添加额外的链接参数
item1
<div class="menu-itemfirst">
<a onfocus="blurLink(this);" href="planner/">planner</a></div>
item2
<div class="menu-item">
<a onfocus="blurLink(this);" href="concept/">Concept</a>
</div>
etc….
看起来应该是这样......
item1
<div class="menu-itemfirst">
<a onfocus="blurLink(this);" href=„int/kdb/eng/planner/">planner</a></div>
item2
<div class="menu-item">
<a onfocus="blurLink(this);" href="concept/">Concept</a>
</div>
etc….
添加参数:int / kdb(静态)和eng(动态,语言键)
我的TS:
lib.mainNavigation = HMENU
lib.mainNavigation {
special =
excludeUidList =
1 = TMENU
1 {
noBlur = 0
NO {
allWrap = <div class="menu-itemfirst"> | </div><div class="menuline"></div> || <div class="menu-item"> | </div><div class="menuline"></div> || <div class="menu-item"> | </div><div class="menuline"></div>
stdWrap.htmlSpecialChars = 1
}
ACT = 1
ACT {
allWrap = <div class="menu-itemfirst-act" style="padding-left:0;"> | </div><div class="menuline"></div> || <div class="menu-item-act"> | </div><div class="menuline"></div> || <div class="menu-item-act"> | </div><div class="menuline"></div>
stdWrap.htmlSpecialChars = 1
}
}
}
答案 0 :(得分:0)
您可以将菜单拆分为两部分,然后使用 COA 。例如。像这样的东西:
lib.mainNavigation = COA
lib.mainNavigation.10 = HMENU
lib.mainNavigation.10 {
1 = TMENU
1 {
maxItems = 1
NO {
allWrap = <div class="menu-itemfirst"> | </div><div class="menuline"></div>
stdWrap.htmlSpecialChars = 1
doNotLinkIt = 1
stdWrap.wrap = <a onfocus="blurLink(this);" href="int/kdb/{$config.language}/planner/">|</a>
}
ACT = 1
ACT < .NO
ACT.allWrap = <div class="menu-itemfirst-act" style="padding-left:0;"> | </div><div class="menuline"></div>
}
}
lib.mainNavigation.20 = HMENU
lib.mainNavigation.20 {
1 = TMENU
1 {
noBlur = 0
begin = 2
NO {
allWrap = <div class="menu-item"> | </div><div class="menuline"></div>
stdWrap.htmlSpecialChars = 1
}
ACT = 1
ACT < .NO
ACT.allWrap = <div class="menu-item-act"> | </div><div class="menuline"></div>
}
}
请注意,您需要拥有名称 config.language 的常量,这与您的语言映射和语言TS consitions中的更改相对应。当然,您可以将名称更改为更合适,但不要忘记在菜单的TS中更改名称。
此外,我没有测试此代码,但你应该知道,该怎么做。