Question

我开始写一本C＃书，我决定把RegEx放到混音中，让枯燥的控制台练习更有趣。我想要做的是在控制台中询问用户他们的电话号码，根据RegEx进行检查，然后捕获数字，这样我就可以按照我想要的方式对其进行格式化。除了RegEx捕获部分之外，我已经完成了所有工作。如何将捕获值转换为C＃变量？

也可随意更正任何代码格式或变量命名问题。

static void askPhoneNumber()
{
    String pattern = @"[(]?(\d{3})[)]?[ -.]?(\d{3})[ -.]?(\d{4})";

    System.Console.WriteLine("What is your phone number?");
    String phoneNumber = Console.ReadLine();

    while (!Regex.IsMatch(phoneNumber, pattern))
    {
        Console.WriteLine("Bad Input");
        phoneNumber = Console.ReadLine();
    }

    Match match = Regex.Match(phoneNumber, pattern);
    Capture capture = match.Groups.Captures;

    System.Console.WriteLine(capture[1].Value + "-" + capture[2].Value + "-" + capture[3].Value);
}

Answer 1

C＃正则表达式API可能非常令人困惑。有组和捕获：

组代表一个捕获组，它用于从文本中提取子字符串
如果组出现在量词中，则每个组可以有多个捕获。

层次结构是：

匹配
- 组
  - 捕获

（匹配可以有多个组，每个组可以有多个捕获）

例如：

Subject: aabcabbc
Pattern: ^(?:(a+b+)c)+$

在此示例中，只有一个组：(a+b+)。该组位于量词内，并且匹配两次。它会生成两个捕获：aab和abb：

aabcabbc
^^^ ^^^
Cap1  Cap2

当一个组不在量词内时，它只生成一个捕获。在您的情况下，您有3个组，每组捕获一次。您可以使用match.Groups[1].Value，match.Groups[2].Value和match.Groups[3].Value来提取您感兴趣的3个子字符串，而无需依靠捕获概念。

Answer 2

匹配结果可能很难理解。我写了这段代码，以帮助我理解已发现的内容和位置。目的是将输出的部分（来自标有//**的行）复制到程序中，以利用匹配中找到的值。

public static void DisplayMatchResults(Match match)
{
    Console.WriteLine("Match has {0} captures", match.Captures.Count);

    int groupNo = 0;
    foreach (Group mm in match.Groups)
    {
        Console.WriteLine("  Group {0,2} has {1,2} captures '{2}'", groupNo, mm.Captures.Count, mm.Value);

        int captureNo = 0;
        foreach (Capture cc in mm.Captures)
        {
            Console.WriteLine("       Capture {0,2} '{1}'", captureNo, cc);
            captureNo++;
        }
        groupNo++;
    }

    groupNo = 0;
    foreach (Group mm in match.Groups)
    {
        Console.WriteLine("    match.Groups[{0}].Value == \"{1}\"", groupNo, match.Groups[groupNo].Value); //**
        groupNo++;
    }

    groupNo = 0;
    foreach (Group mm in match.Groups)
    {
        int captureNo = 0;
        foreach (Capture cc in mm.Captures)
        {
            Console.WriteLine("    match.Groups[{0}].Captures[{1}].Value == \"{2}\"", groupNo, captureNo, match.Groups[groupNo].Captures[captureNo].Value); //**
            captureNo++;
        }
        groupNo++;
    }
}

使用此方法的一个简单示例，给出此输入：

Regex regex = new Regex("/([A-Za-z]+)/(\\d+)$");
String text = "some/directory/Pictures/Houses/12/apple/banana/"
            + "cherry/345/damson/elderberry/fig/678/gooseberry");
Match match = regex.Match(text);
DisplayMatchResults(match);

输出结果为：

Match has 1 captures
  Group  0 has  1 captures '/Houses/12'
       Capture  0 '/Houses/12'
  Group  1 has  1 captures 'Houses'
       Capture  0 'Houses'
  Group  2 has  1 captures '12'
       Capture  0 '12'
    match.Groups[0].Value == "/Houses/12"
    match.Groups[1].Value == "Houses"
    match.Groups[2].Value == "12"
    match.Groups[0].Captures[0].Value == "/Houses/12"
    match.Groups[1].Captures[0].Value == "Houses"
    match.Groups[2].Captures[0].Value == "12"

假设我们想要在上面的文本中找到上述正则表达式的所有匹配项。然后我们可以在代码中使用MatchCollection，例如：

MatchCollection matches = regex.Matches(text);
for (int ii = 0; ii < matches.Count; ii++)
{
    Console.WriteLine("Match[{0}]  // of 0..{1}:", ii, matches.Count-1);
    RegexMatchDisplay.DisplayMatchResults(matches[ii]);
}

这个输出是：

Match[0]  // of 0..2:
Match has 1 captures
  Group  0 has  1 captures '/Houses/12/'
       Capture  0 '/Houses/12/'
  Group  1 has  1 captures 'Houses'
       Capture  0 'Houses'
  Group  2 has  1 captures '12'
       Capture  0 '12'
    match.Groups[0].Value == "/Houses/12/"
    match.Groups[1].Value == "Houses"
    match.Groups[2].Value == "12"
    match.Groups[0].Captures[0].Value == "/Houses/12/"
    match.Groups[1].Captures[0].Value == "Houses"
    match.Groups[2].Captures[0].Value == "12"
Match[1]  // of 0..2:
Match has 1 captures
  Group  0 has  1 captures '/cherry/345/'
       Capture  0 '/cherry/345/'
  Group  1 has  1 captures 'cherry'
       Capture  0 'cherry'
  Group  2 has  1 captures '345'
       Capture  0 '345'
    match.Groups[0].Value == "/cherry/345/"
    match.Groups[1].Value == "cherry"
    match.Groups[2].Value == "345"
    match.Groups[0].Captures[0].Value == "/cherry/345/"
    match.Groups[1].Captures[0].Value == "cherry"
    match.Groups[2].Captures[0].Value == "345"
Match[2]  // of 0..2:
Match has 1 captures
  Group  0 has  1 captures '/fig/678/'
       Capture  0 '/fig/678/'
  Group  1 has  1 captures 'fig'
       Capture  0 'fig'
  Group  2 has  1 captures '678'
       Capture  0 '678'
    match.Groups[0].Value == "/fig/678/"
    match.Groups[1].Value == "fig"
    match.Groups[2].Value == "678"
    match.Groups[0].Captures[0].Value == "/fig/678/"
    match.Groups[1].Captures[0].Value == "fig"
    match.Groups[2].Captures[0].Value == "678"

因此：

    matches[1].Groups[0].Value == "/cherry/345/"
    matches[1].Groups[1].Value == "cherry"
    matches[1].Groups[2].Value == "345"
    matches[1].Groups[0].Captures[0].Value == "/cherry/345/"
    matches[1].Groups[1].Captures[0].Value == "cherry"
    matches[1].Groups[2].Captures[0].Value == "345"

同样适用于matches[0]和matches[2]。

Answer 3

string pattern = @"[(]?(\d{3})[)]?[ -.]?(\d{3})[ -.]?(\d{4})";

System.Console.WriteLine("What is your phone number?");
string phoneNumber = Console.ReadLine();

while (!Regex.IsMatch(phoneNumber, pattern))
{
    Console.WriteLine("Bad Input");
    phoneNumber = Console.ReadLine();
}

var match = Regex.Match(phoneNumber, pattern);
if (match.Groups.Count == 4)
{
    System.Console.WriteLine("Number matched : "+match.Groups[0].Value);
    System.Console.WriteLine(match.Groups[1].Value + "-" + match.Groups[2].Value + "-" + match.Groups[3].Value);
}

如何在C＃中读取RegEx捕获

3 个答案: