Question

我需要一个Python脚本来分析日志文件的内容。日志文件（命名为：log.txt.2014-01-01）的组成如下：

....<different structure>

2013-05-09 19:09:20,112 [1] DEBUG Management.Handle - Action: Amount=005,00; Date=25.04.2013 19:25:04

2013-05-09 19:09:20,112 [1] DEBUG Management.Handle - Action: Amount=005,00; Date=25.04.2013 19:27:05

2013-05-09 19:09:20,112 [1] DEBUG Management.Handle - Action: Amount=005,00; Date=25.04.2013 19:28:05

...<different structure>

我需要总结Amount并打印总数。

Answer 1

这是regular expressions的工作：

import re
from cStringIO import StringIO

def extractAmount(file_like):
    amountRe = re.compile('^.* Management\.Handle - Action: Amount=(\d+),(\d+);')
    for line in file_like:
        result = amountRe.match(line)
        if result:
            matches = result.groups()
            yield (float(matches[0]) + (float(matches[1]) / 100.0))

data = StringIO("""....<different structure>
2013-05-09 19:09:20,112 [1] DEBUG Management.Handle - Action: Amount=005,00; Date=25.04.2013 19:25:04
2013-05-09 19:09:20,112 [1] DEBUG Management.Handle - Action: Amount=005,00; Date=25.04.2013 19:27:05
2013-05-09 19:09:20,112 [1] DEBUG Management.Handle - Action: Amount=005,00; Date=25.04.2013 19:28:05
...<different structure>""")

print sum(extractAmount(data))

在示例中，我使用了cStringIO对象来加载数据，但是这种方法应该适用于任何提供字符串的迭代（例如来自open的文件对象）。 / p>

Answer 2

import re
x=<your_test_string>
z= [float(re.sub(r",",".",i)) for i in re.findall(r"(?<=DEBUG Management\.Handle - Action: Amount=)([^;]+)",x)]
print sum(z)

你可以试试这个。

尝试

http://www.pythontutor.com/visualize.html#code=import+re%0Ax%3D%22%22%22....%3Cdifferent+structure%3E%0A%0A2013-05-09+19%3A09%3A20,112+%5B1%5D+DEBUG+Management.Handle+-+Action%3A+Amount%3D005,00%3B+Date%3D25.04.2013+19%3A25%3A04%0A%0A2013-05-09+19%3A09%3A20,112+%5B1%5D+DEBUG+Management.Handle+-+Action%3A+Amount%3D005,00%3B+Date%3D25.04.2013+19%3A27%3A05%0A%0A2013-05-09+19%3A09%3A20,112+%5B1%5D+DEBUG+Management.Handle+-+Action%3A+Amount%3D005,00%3B+Date%3D25.04.2013+19%3A28%3A05%0A%0A...%3Cdifferent+structure%3E%22%22%22%0Az%3D+%5Bfloat(re.sub(r%22,%22,%22.%22,i))+for+i+in+re.findall(r%22(%3F%3C%3DDEBUG+Management%5C.Handle+-+Action%3A+Amount%3D)(%5B%5E%3B%5D%2B)%22,x)%5D%0Aprint+sum(z)&mode=display&origin=opt-frontend.js&cumulative=false&heapPrimitives=false&drawParentPointers=false&textReferences=false&showOnlyOutputs=false&py=2&rawInputLstJSON=%5B%5D&curInstr=7

如何从日志文件中打印和汇总特定数据

2 个答案: