Question

我一直收到错误：Uncaught TypeError：无法读取未定义的属性'create' 我做了一个console.log并返回了数组。例如：

[
  {
    "comment_id":"702542",
    "parcel_id":"166865",
    "user_id":"10034",
    "comment":"2014+ LCV RESPONSE - FINAL LETTER (07-JAN-2014) RECEIVED 01\/13\/2014 COMPLETED AS PRIMARY RESIDENCE - LEGAL CLASS NOT UPDATED.",
    "date_created":"2014-01-30 01:00:00"
  }
]

当用户点击查看评论按钮时，我似乎无法在jquery对话框中填充表格。

以下是jquery代码：已更新

    $('#ViewComments').click(function() {
        $("#InsertComment").focus();
        //view/add comments dialog
        $( "#CommentsDialog" ).dialog({
            height:320,
            width: 500,
            modal:true,
            closeOnEscape:true,
            buttons: [ { text: "Close", click: function() { $(this).dialog( "close" ); } } ]
        });
        var parcel_id = $('#ParcelId').val();
        $.ajax({
            url: "classes/get-comments.php?parcel_id=" + parcel_id,
            type: "GET",
            data: { parcel_id : parcel_id },
            error: function(SMLHttpRequest, textStatus, errorThrown){
                    alert("An error has occurred making the request: " + errorThrown);
            },
            success: function(comments){
                //do stuff here on success
                //console.log(comments);
                for(var i=0; i < comments.length; i++){
                    var tr = $('<tr></tr>');
                    tr.append("<td>" + comments[0].date_created + "</td><td style=\"text-align:right;\">" + comments[0].user_id + "</td></tr><tr><td colspan=\"2\">" + comments[0].comment + "</td>");
                    $('#CommentResults').append(tr);
                    //console.log(tr);
                }
            }
        });
    });//end view comments click function

HTML：

    <div id="CommentsDialog" title="Comments">
        <div style="width:98%;height:75%; margin-bottom:5px; background-color: #fff; padding:5px;" id="Comments" name="Comments">
            <table id="CommentResults" name="CommentResults"></table>               
        </div>
        <input type="text" style="width:65%;margin-top:5px;" id="InsertComment" /> <input type="button" id="AddComment" value="Add Comment" class="floatRight" />
        </form>
    </div>

Answer 1

在您的ajax请求中，添加：

dataType: "json"

未捕获的TypeError：尝试在jquery中循环遍历json数组时，无法读取未定义的属性'create'

1 个答案: