Question

这个错误是什么意思？我怎样摆脱这个问题？

Traceback (most recent call last):
  File "bestcodeever.py", line 16, in <module>
    html=urllib2.urlopen('http://' + fulllink).read()
  File "/usr/lib/python2.7/urllib2.py", line 127, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.7/urllib2.py", line 410, in open
    response = meth(req, response)
  File "/usr/lib/python2.7/urllib2.py", line 523, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib/python2.7/urllib2.py", line 448, in error
    return self._call_chain(*args)
  File "/usr/lib/python2.7/urllib2.py", line 382, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 531, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 503: Service Unavailable

Answer 1

HTTP 503状态代码表示您尝试联系的Web服务器不可用（可能是出于维护原因）。它仍然能够使用此代码做出最低限度的响应，因此它不会脱机并且正在侦听请求，它只是暂时不返回您想要的服务：稍后再试。

如果您最近对Python脚本的要求太高，那么您的IP地址也可能被服务器列入黑名单......

如何删除此错误？

1 个答案: