Question

这是我的实体类。

@Entity
public class Profile {

@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private Long profileId;

@Transient
private String name;

@ElementCollection(fetch = FetchType.EAGER)
private Map<String, String> trNames;     //Key: LanguageCode, Value: translated text
...
}

ProfileRepository类

public interface ProfileRepository extends JpaRepository<Profile, Long> {

//This method should go through the Map Collection and return a profile whose name matches the given parameter value.
Profile findByTrNames(String code, String name);

}

我创建了一个JUnit Test Class来测试这个方法。这行代码

Profile found = repository.findByTrNames("en", "Interview IT");

抛出异常。

org.springframework.dao.InvalidDataAccessApiUsageException: Parameter value [en] did not match expected type [java.util.Map]; nested exception is java.lang.IllegalArgumentException: Parameter value [en] did not match expected type [java.util.Map]
    at org.springframework.orm.jpa.EntityManagerFactoryUtils.convertJpaAccessExceptionIfPossible(EntityManagerFactoryUtils.java:301)
    at etc..

有人可以帮助我吗？

非常感谢。

Answer 1

这应该有效

@Query("select p from Profile p where p.trNames[?1] = ?2")
Profile findByTrNames(String code, String name);

<强>更新

创建JIRA票证以支持此功能：https://jira.spring.io/browse/DATAJPA-643

Spring Framework：findBy抛出非法参数异常

1 个答案: