在写入代码的文件中填充了组合框的值:
<select id="company" required="required" class="form-control" value = "select" name="subject_code" placeholder="Select" >
<?php
//Iterating list of subjects available to be filled .
echo "<option> Select </option>";
foreach ($subjects_to_fill as $subject_id => $subject_name) {
# code...
echo "<option value=".$subject_id."> ".$subject_name." </option>";
}
?>
</select>
在从组合框中选择特定项目时,我希望根据faculty_table
从$subject_id
动态显示faculty_name。
表格结构:
faculty_table(faculty_id,faculty_name,subject_id)
subject_table(subject_id,subject_name,faculty_id)
答案 0 :(得分:0)
您需要使用ajax执行此任务。
在当前文件中添加<div>
及以下脚本。
<div id="faculty"></div>
<script type="text/javascript">
function get_faculty()
{
var id = document.getElementById("company").value;
var dataString = 'id='+ id;
$.ajax
({
type: "POST",
url: "get_faculty.php",
data: dataString,
success: function(html)
{
$("#faculty").html(html);
}
});
}
</script>
现在在同一文件夹中创建另一个get_faculty.php文件,该文件将在公司下拉列表的onchange事件中调用。
在该文件中写下以下代码
if($_POST['id'])
{
$id=$_POST['id'];
$con=mysqli_connect("localhost","username","pass","dbname");
$sql=mysqli_query($con,"SELECT faculty_name from faculty_table where subject_id = ".$id);
while($row=mysqli_fetch_array($sql))
{
echo $row['faculty_name'];
}
}
别忘了写mysqli_connect凭据并进行相应的查询。