cvc-elt.1：找不到元素'beans'的声明

Question

我正在尝试使用Spring Security来验证bean对象的用户登录功能：

    ApplicationContext context = new ClassPathXmlApplicationContext(
            "com/humandevice/drive/fx/util/applicationContext.xml");
    authenticationManager = (AuthenticationManager) context
            .getBean("authenticationManager");

我的applicationContext.xml位于以下位置：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans.xsd
       http://www.springframework.org/schema/security
       http://www.springframework.org/schema/security/spring-security-3.2.xsd
       http://www.springframework.org/schema/context
       http://www.springframework.org/schema/context/spring-context.xsd"
xmlns:context="http://www.springframework.org/schema/context">
<context:component-scan base-package="com.humandevice.drive.fx">
    <context:include-filter type="regex"
        expression="com.humandevice.drive.fx.*" />
</context:component-scan>
<bean id="LoginController" alias="loginController" class="controller.LoginController">
    <property name="authenticationManager" ref="authenticationManager" />
    <property name="applicationContext" ref="applicationContext" />
</bean>
<bean id="applicationContext" alias="applicationContext"
    class="org.springframework.context.ApplicationContext;">
</bean>
<authentication-manager alias="authenticationManager">
    <authentication-provider user-service-ref="userService">
        <password-encoder ref="bCryptPasswordEncoder" />
    </authentication-provider>
</authentication-manager>
 </beans>

但我得到了这个例外：

Caused by: org.xml.sax.SAXParseException; lineNumber: 9; columnNumber: 64; cvc-elt.1: Cannot find the declaration of element 'beans'.

我很难理解这个问题。

<小时/>的更新 <小时/>

我对XML进行了一些更改：

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
    xmlns:task="http://www.springframework.org/schema/task"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/task http://www.springframework.org/schema/task/spring-task.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
        http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.2.xsd">

    <import resource="/context-service.xml" />
    <import resource="/context-repository.xml" />

    <context:component-scan base-package="com.humandevice.drive.fx"></context:component-scan>

    <authentication-manager>
        <authentication-provider user-service-ref="com.humandevice.drive.service.user.IUserService">
            <password-encoder ref="bCryptPasswordEncoder" />
        </authentication-provider>
    </authentication-manager>
</beans:beans>

我现在收到这个例外：

lineNumber: 11; columnNumber: 44; cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'import'.

Answer 1

您的默认命名空间是http://www.springframework.org/schema/security，并且您配置了xmlns:beans="http://www.springframework.org/schema/beans"这意味着您必须将前缀beans:添加到所有标记格式http://www.springframework.org/schema/beans，以便您的XML应如下所示

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
       xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans.xsd
       http://www.springframework.org/schema/security
       http://www.springframework.org/schema/security/spring-security-3.2.xsd
       http://www.springframework.org/schema/context
       http://www.springframework.org/schema/context/spring-context.xsd"
       xmlns:context="http://www.springframework.org/schema/context">
    <context:component-scan base-package="com.humandevice.drive.fx">
        <context:include-filter type="regex"
                                expression="com.humandevice.drive.fx.*" />
    </context:component-scan>
    <beans:bean id="LoginController" alias="loginController" class="controller.LoginController">
        <beans:property name="authenticationManager" ref="authenticationManager" />
        <beans:property name="applicationContext" ref="applicationContext" />
    </beans:bean>
    <beans:bean id="applicationContext" alias="applicationContext"
          class="org.springframework.context.ApplicationContext;">
    </beans:bean>
    <authentication-manager alias="authenticationManager">
        <authentication-provider user-service-ref="userService">
            <password-encoder ref="bCryptPasswordEncoder" />
        </authentication-provider>
    </authentication-manager>
</beans:beans>

Answer 2

对我来说，我只是在同一个地方剪切并粘贴并保存XML文件，这对我有用!!

Answer 3

此代码可以帮助您。

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:context="http://www.springframework.org/schema/context" 
xmlns:aop="http://www.springframework.org/schema/aop" 
xsi:schemaLocation="
http://www.springframework.org/schema/beans 
classpath:/org/springframework/beans/factory/xml/spring-beans-3.0.xsd 
http://www.springframework.org/schema/context 
classpath:/org/springframework/context/config/spring-context-3.0.xsd
http://www.springframework.org/schema/aop 
classpath:/org/springframework/aop/config/spring-aop-3.0.xsd
">      
</beans>

Answer 4

对于我来说，applicationContext.xml的更改在类路径中没有更新。所以我从classpath中手动删除了applicationContext.xml文件，并重新构建解决了我的问题的应用程序

Answer 5

我完全不确定为什么会有这种奇怪的行为。我也面临同样的例外，并遵循Karthikeyan Vaithilingam的建议。但是问题仍然没有解决。因此，我已还原所做的更改并保存了文件。中提琴！异常消失了，现在没有错误。

Answer 6

我遇到了类似的问题，我想再举一个可能原因的例子。

原始 .xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="https://www.springframework.org/schema/mvc"
        xmlns:xsi="https://www.w3.org/2001/XMLSchema-instance" xmlns:beans="https://www.springframework.org/schema/beans"
        xmlns:context="https://www.springframework.org/schema/context" xmlns:tx="https://www.springframework.org/schema/tx"
        xsi:schemaLocation="https://www.springframework.org/schema/mvc https://www.springframework.org/schema/mvc/spring-mvc.xsd
            https://www.springframework.org/schema/beans https://www.springframework.org/schema/beans/spring-beans.xsd
            https://www.springframework.org/schema/context https://www.springframework.org/schema/context/spring-context.xsd
            https://www.springframework.org/schema/tx https://www.springframework.org/schema/tx/spring-tx-4.0.xsd">

工作.xml：

<?xml version="1.0" encoding="UTF-8"?>
<beans
    xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc 
    http://www.springframework.org/schema/mvc/spring-mvc.xsd
    http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context 
    http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://www.springframework.org/schema/tx 
    http://www.springframework.org/schema/tx/spring-tx-4.0.xsd">

解决方案：

1. 使用 xmlns="http://www.springframework.org/schema/beans" 作为基础 xmlns。删除 beans: 前缀
2. 将 https 更改为 http

Answer 7

我在尝试创建可执行 jar 时遇到了同样的错误。我有

ApplicationContext context = new ClassPathXmlApplicationContext("classpath:context.xml");

而不是（注意类路径后的 *）

ApplicationContext context = new ClassPathXmlApplicationContext("classpath*:context.xml");