Question

这是一个显示最便宜的鞋子的程序。数据来自文本文件。在我输入鞋子的颜色，制造商和类型后，我收到以下错误消息：

java.lang.NumberFormatException: For input string: "Price"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at Boots.main(Boots.java:47)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at edu.rice.cs.drjava.model.compiler.JavacCompiler.runCommand(JavacCompiler.java:272)

我在我的智慧结束。请帮忙！

这是代码。

import java.util.Scanner; 
import java.io.*; 
import java.util.StringTokenizer;

public class Boots
{
  public static void main(String[] args) throws IOException
  {
   Scanner keyboard = new Scanner(System.in); 

   String manufact, color, type; 

   System.out.print("Enter the boot manufacturer."); 
   manufact = keyboard.nextLine(); 
   manufact = manufact.replaceAll("\\s+", ""); 
   System.out.print("Enter the type of boot."); 
   type = keyboard.nextLine();  
   type = type.replaceAll("\\s+", ""); 
   System.out.print("Enter the boot color."); 
   color = keyboard.nextLine();     
   color = color.replaceAll("\\s+", "");    

   /* Open boots.txt.*/

    File inputFile = new File("Boots.txt"); 
    if (!inputFile.exists()) System.out.print("I'm sorry, we are experiencing technical difficulties. Please try again later."); 
    Scanner warehouse = new Scanner(inputFile); 

    String[] compData = new String[25]; 

    int price = 0; // cheapest pair of shoes 
    String finalVendor = ""; 
    String finalType = ""; 
    String finalManufact = ""; 
    String finalColor = ""; //information of cheapest pair of shoes

    /* Read through file, and save each line as a compData array, each word tokenized as a compData subarray.*/ 

    do {
      String nLine = warehouse.nextLine(); 
      StringTokenizer tokens = new StringTokenizer(nLine);
      for (int i = 0; i<5; i++)
            {
             compData[i] = tokens.nextToken(); 
            }

      int priceParsed = Integer.parseInt(compData[4]); 
      if (compData[1].equalsIgnoreCase(manufact))
            if (compData[3].equalsIgnoreCase(color))
                if (compData[2].equalsIgnoreCase(type))
                    if (priceParsed <= price) 
                      { 
                        price = priceParsed; 
                        finalVendor = compData[0]; finalManufact = compData[1]; finalType = compData[2]; finalColor=compData[3]; 
      }
    } while (warehouse.hasNext());

    if (price<=0)
    {System.out.printf("Meet your new shoes!\nThey are %s %s by %s. You can get them for $%.2s at %s.", finalColor, 
                       finalType, finalVendor, finalManufact, price);} else {System.out.print("We have no such merchandise at this time.");};

    warehouse.close(); 
    keyboard.close(); 
  }
  }

Answer 1

你所要做的就是添加=＆＃34;＆＃34 ;;到String变量声明的末尾。

String finalVendor = ""; 
String finalType = ""; 
String finalManufact = ""; 
String finalColor = ""; //information of cheapest pair of shoes

这将消除您的错误。如果你遇到parseInt问题，你需要检查你正在查看的数组中的内容，并确保从令牌器中获取正确的数据。

代码中的运行时错误 - ＆＃34; NumberFormatException＆＃34;

1 个答案: