Question

我能够连接到mysql数据库但是我无法将表单中的数据显示到我的数据库中。我不知道为什么会这样，但我能够从我的数据库中检索数据我只是无法输入信息。现在我只想输入First_Name。在向表单输入数据时，我也没有错误。任何帮助将不胜感激!!

   <p>
  <form name="input1" action="http://seanfagan.webuda.com/Final/club.php" method="post">
   First_Name:<input type="text" name="First_Name"><br>
   Last_Name: <input type="text" name="Last_Name"><br>
   Club_Name: <input type="text" name="Club_Name"><br>
   Email:     <input type="text" name="Email"><br>
   Club_Type: <input type="text" name="Club_Type"><br>
   Members: <input type="text" name="Members"><br>
  <input type="submit" value="Send"><br>
   </form>
   <?php
   $mysql_host = "mysql14.000webhost.com";
   $mysql_database = "a9576602_Final";
   $mysql_user = "a9576602_Final";
   $mysql_password = "*****![enter image description here][1]";
   $mysql_error = "Could not connect to database!";

   $conn = mysql_connect($mysql_host, $mysql_user, $mysql_password) or die ("$mysql_error");
   $select_db= mysql_select_db('a9576602_Final') or die ("Couldn't select database!");

   $value = $_Post['input1'];
   $sql = "INSERT INTO Club (First_Name) VALUES ('First_Name')";

   if (!mysql_query($sql)) {
      die('Errorss: ' . mysql_error());
       }


  mysql_close();

 ?>
 </p>

Answer 1

假设您与数据库的连接没问题。您可以为提交按钮添加<name>属性，以作为通过$ _POST方法发送表单的参考：

<input type = "submit" name = "input1" value = "Submit">

然后使用它，你可以触发你的insert语句：

<?php
     if(isset($_POST['input1']))
       {
          // make sure you also declare the variables in your form such as the first name, etc.
          $firstName = $_POST['First_Name'];
          mysql_query("INSERT INTO Club (First_Name) VALUES ('$firstName')");
       }
?>

希望这可以帮助你：D

将表单连接到SQL数据库

1 个答案: